4 = (r-2) t
8 = (r+2) t
4 = (r-2) * [8/(r+2)]
4 = (8r-16)/ (r+2) . . .multiply by 2
4r + 8 = 8r - 16
4r = 24
r = 6
hope this helps
Answers:
x = 4
EF = 14
CF = 7
EC = 7
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Work Shown:
C is the midpoint of segment EF. This means that EC = CF. In other words, the two pieces are congruent.
Use substitution and solve for x
EC = CF
5x-13 = 3x-5
5x-13+13 = 3x-5+13
5x = 3x+8
5x-3x = 3x+8-3x
2x = 8
2x/2 = 8/2
x = 4
Now that we know that x = 4, we can use this to find EC and CF
Let's compute EC
EC = 5x - 13
EC = 5*x - 13
EC = 5*4 - 13 ... replace x with 4
EC = 20 - 13
EC = 7
Let's compute CF
CF = 3x - 5
CF = 3*x - 5
CF = 3*4 - 5 ... replace x with 4
CF = 12 - 5
CF = 7
As expected, EC = CF (both are 7 units long).
By the segment addition postulate, we can say EC+CF = EF
EC+CF = EF
EF = EC+CF
EF = 7+7
EF = 14
ANSWER:
The right option is d)
As 5*1=5
5*3=15
5*4=20
HOPE IT HELPS!!!!!
PLEASE MARK BRAINLIEST!!!!
Answer:
<u>$7000</u> of his salary is put into his account each quarter.
Step-by-step explanation:
Given:
An investment broker puts 1/12 of his paycheck into a retirement account every quarter.
His salary is $84,000.
Now, to find the amount of his salary put into his account each quarter.
So,to get the amount of his salary:




Therefore, $7000 of his salary is put into his account each quarter.