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3 years ago

PLZ HELP FAST how do you find the surface area of a rectangle prism.

Mathematics

2 answers:

Anon25 [30]3 years ago

3 0

Find the dimensions of the rectangular prism

makvit [3.9K]3 years ago

3 0

A=2(wl+hl+hw)

w=width
l=length
h=height

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My salary is £28,860 per year. What is my hourly rate of pay if I work 37 hours a week

Nostrana [21]

Answer:

pay rate £7.80

Step-by-step explanation:

28860 divide by 37 = 780

780 divided by 100 = 7.80

4 0

3 years ago

How much will it cost to borrow $2,500 for a year at a simple interest rate at 14% please explain

Mariana [72]

Principle (P) = $ 2,500

Rate (R) = 14%

Time (T) = 1 year

Simple Interest (SI) = $\frac{PRT}{100}$

SI = $\frac{2500 * 14 * 1}{100} = \frac{25 *14}{1} = 350$

Hence, the answer is $350.

3 0

3 years ago

Evaluate the expression 14C2

lisabon 2012 [21]

$\bf _nC_r= \cfrac{n!}{r!(n-r)!}\qquad \qquad _{14}C_2=\cfrac{14!}{2!(14-2)!}$

5 0

3 years ago

Find the next three terms of the sequence. Then write a rule for the sequence.

g100num [7]

We notice it diviides by 3 each time or multiplies by 1/3
common ratio is 1/3
first term is 648

so next 3 terms are 8, 8/3, and 8/9

rule is an=648(1/3)^(n-1)

8 0

3 years ago

A jeweler wants to make 14 grams of an alloy that is precisely 75% gold.. The jeweler has alloys that are 25% gold, 50% gold, &a

Goryan [66]

Given that the jeweler has alloys that are 25% gold, 50% gold, and 82% gold.

As he wants to make 14 grams of an alloy by adding two different alloys that is precisely 75% gold, so one alloy must have a percentage of gold more than 75%.

One alloy is 82% gold and, the second can be chosen between 25% gold, 50% gold, so there are two cases.

Case 1: 82% gold + 50% gold

Let x grams of 82% gold and y grams of 50% gold added to make x+y=14 grams of 75% gold, so

75% of 14 = 82% of x + 50% of y

$\Rightarrow 75/100 \times 14 = 82/100 \times x + 50/100 \times y \\\\$

$\Rightarrow 75/100 \times 14 = 82/100 \times x + 50/100 \times (14-x)$ [as x+y=14]

$\Rightarrow 75 \times 14 = 82 \times x + 50 \times (14-x) \\\\\Rightarrow 75 \times 14 = 82 \times x + 50 \times14-50\times x \\\\\Rightarrow 75 \times 14 = 32 \times x + 50 \times14 \\\\\Rightarrow 32 \times x =75 \times 14 - 50 \times14 \\\\$

$\Rightarrow x =(25 \times 14)/32=10.9375$ grams

and $y = 14-x= 14-10.9375=3.0625$ grams.

Hence, 10.9375 grams of 82% gold and 3.0625 grams of 50% gold added to make 14 grams of 75% gold.

Case 2: 82% gold + 25% gold

Let x grams of 82% gold and y grams of 25% gold added to make x+y=14 grams of 75% gold, so

75% of 14 = 82% of x + 25% of y

$\Rightarrow 75/100 \times 14 = 82/100 \times x + 25/100 \times y \\\\\Rightarrow 75/100 \times 14 = 82/100 \times x + 25/100 \times (14-x) \\\\ \Rightarrow 75 \times 14 = 82 \times x + 25 \times (14-x) \\\\\Rightarrow 75 \times 14 = 82 \times x + 25 \times14-25\times x \\\\\Rightarrow 75 \times 14 = 57 \times x + 25 \times14 \\\\\Rightarrow 57 \times x =75 \times 14 - 25 \times14 \\\\$

$\Rightarrow x =(50 \times 14)/57=12.28$ grams

and $y = 14-x= 14-12.28=1.72$ grams.

Hence, 12.28 grams of 82% gold and 1.72 grams of 50% gold added to make 14 grams of 75% gold.

3 0

3 years ago