This is a lot of information at once, so break down the question step by step!
1) You are told that 34.6% of Mr. Camp's class of 26 students reported that they have at least 2 siblings. Find the number of students in his class that have at least two siblings by multiplying 0.346 (the decimal form of 34.6%) by 26:
0.346 x 26 = 9 students
However, be careful! Notice that you want the number of students with fewer than 2 siblings. That means you need to subtract 9 from 26 to find the number of students with less than 2 siblings:
26 - 9 = 17 students
2) You are told that there are 1800 eighth-grade classes in the state, and the average size of the classes is 26. That means you can assume that there are 1800 classes of 26 in the state.
Since you are told that Mr. Camp's class is representative of students in the state's 8th grade classes. That means in the state, for each class of 26, 17 students (the number we figured out in step 1) have fewer than two siblings!
For each of the 1800 classes of 26, 17 students have fewer than two siblings. That means you need to multiply 1800 classes by 17 students per class to get your final answer, which is answer C:
1800 x 17 = 30,600
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Answer: C) 30,600
Answer:
C. the cylinder because it has approximately 11.6 less wasted space than the prism.
Step-by-step explanation:
Answer:
Yes, its a linear function.
Step-by-step explanation:
Answer:
25
Step-by-step explanation:
Each of the 16 "ratio units" representing all 80 dancers must stand for ...
(80 dancers)/(16) = 5 dancers
Then 5 "ratio units" representing seventh-grade dancers will stand for ...
5 × 5 dancers = 25 dancers
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Another way to figure this is to write the proportion ...
(seventh-grade dancers)/(all dancers) = 5/16
seventh-grade dancers = (all dancers)×(5/16) = 80×5/16
seventh-grade dancers = 25
Answer: 0.9862
Step-by-step explanation:
Given : The probability that the chips belongs to Japan: P(J)= 0.36
The probability that the chips belongs to United States : P(U)= 1-0.36=0.64
The proportion of Japanese chips are defective : P(D|J)=0.017
The proportion of American chips are defective : P(D|U)=0.012
Using law of total probability , we have
Thus , the probability that chip is defective = 0.0138
Then , the probability that a chip is defect-free=
