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Scilla [17]
3 years ago
8

Which of the following numbers can be expressed as repeating decimals? 3 over 7, 2 over 5, 3 over 4, 2 over 9

Mathematics
1 answer:
Maurinko [17]3 years ago
6 0

Hello!

Let's think about the denominators we have. A seventh goes on forever in no specified order. A fifth an a fourth have set decimal values, 0.2 and 0.25, so they are not repeating decimals. A ninth is 0.111111..., it repeats like this forever in a specified order. Therefore, 2/9, or 0.222222...., would be a repeating decimal.

Therefore, our answer is \boxed {\frac{2}{9}}.

I hope this helps!

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alex41 [277]
Vol of sphere =4/3πr³
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vol of cone =1/3πx²h
when h=r, =1/3πrx²
since they have the same volume,
4/3πr³=1/3πrx²
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x²=4r²
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For what value of x does 3^4x=27^x-3?
Setler79 [48]

x=4.80989686

by simplifying both sides of the equation, then isolating the variable.

4 0
3 years ago
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I need help with this question
Rudiy27
Since the angle is positive, you can find any coterminal angle by applying:


Angle + x = 2π ==> 7π/6 + x = 2π ==> x = 2π - 7π/6

x= 12π/6 -7π/6 = 5π/6

So the angle 5π/6 is the coterminal of 7π/6
8 0
3 years ago
Ayo runs a fairground game.In each turn, a player rolls a fair dice numbered 1 - 6 and spins a fair spinner numbered 1 - 12.It c
aksik [14]

Using the definition of expected value, it is found that Ayo can be expected to make a profit of £55.8.

The <em>expected value</em> is given by the <u>sum of each outcome multiplied by it's respective probability.</u>

In this problem:

  • The player wins $6, that is, Ayo loses £6, if he rolls a 6 and spins a 1, hence the probability is \frac{1}{6} \times \frac{1}{12} = \frac{1}{72}.
  • The player wins $3, that is, Ayo loses £3, if he rolls a 3 on at least one of the spinner or the dice, hence, considering three cases(both and either the spinner of the dice), the probability is \frac{1}{6} \times \frac{1}{12} + \frac{1}{6} \times \frac{11}{12} + \frac{5}{6} \times \frac{1}{12} = \frac{1 + 11 + 5}{72} = \frac{17}{72}
  • In the other cases, Ayo wins £1.40, with 1 - \frac{18}{72} = \frac{54}{72} probability.

Hence, his expected profit for a single game is:

E(X) = -6\frac{1}{72} - 3\frac{17}{72} + 1.4\frac{54}{72} = \frac{-6 - 3(17) + 54(1.4)}{72} = 0.2583

For 216 games, the expected value is:

E = 216(0.2583) = 55.8

Ayo can be expected to make a profit of £55.8.

To learn more about expected value, you can take a look at brainly.com/question/24855677

6 0
3 years ago
Help me pls help me
coldgirl [10]
1st
0.3/100*15000
=45
2nd
40/200*100
=20
=
3 0
3 years ago
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