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xz_007 [3.2K]
3 years ago
11

What is the greatest possible whole number remainder if you divide any number by 41

Mathematics
2 answers:
telo118 [61]3 years ago
8 0

Answer:

40

Step-by-step explanation:

we have to find the greatest possible whole number remainder if you divide any number by 41

Let us consider following examples

1. if we divide 78 by 41 , the remainder is 37

2. if we divide 79 by 41, the remainder is 38

3. If we divide 80 by 41, the remainder is 39

4. If we divide 81 by 41, the remainder is 40.

5. If we divide 82 by 41, the remainder is 41, 82 will be completely divided by 41, hence the remainder is 0.

so, the greatest possible remainder is 40.

Hence, the correct answer is 40.

Dima020 [189]3 years ago
7 0
40. Divide 81 by 41. 41 goes into 81 once with a remainder of 40
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Suppose you and a friend each choose at random an integer between 1 and 8, inclusive. For example, some possibilities are (3,7),
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Answer and explanation:

Given : Suppose you and a friend each choose at random an integer between 1 and 8, inclusive.

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(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)   (2,7) (2,8)

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(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)   (6,7) (6,8)

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The probability is given by,

\text{Probability}=\frac{\text{Favorable outcome }}{\text{Total outcome}}

a) p(you pick 5 and your friend picks 8)

The favorable outcome is (5,8)= 1

\text{Probability}=\frac{1}{64}

b) p(sum of the two numbers picked is < 4)

The favorable outcome is (1,1), (1,2), (2,1)= 3

\text{Probability}=\frac{3}{64}

c) p(both numbers match)

The favorable outcome is (1,1), (2,2), (3,3), (4,4), (5,5), (6,6), (7,7), (8,8) = 8

\text{Probability}=\frac{8}{64}

\text{Probability}=\frac{1}{8}

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