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DiKsa [7]
3 years ago
10

What’s the answer?? I’m so done with this MobyMax stuff...

Mathematics
2 answers:
Karolina [17]3 years ago
5 0
180-11=169
its 180 because straight line
BartSMP [9]3 years ago
5 0

Answer:

169

Step-by-step explanation:

Since the base of the angle is a straight angle which is 180 degrees, and angle A is 11 degrees, you have to subtract 180 - 11 = _____

____ =  169

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Which of the following is Not a way to prove triangles are congruent.​
andrew-mc [135]

Answer:

AAA

Step-by-step explanation:

4 0
3 years ago
(3x - 2)<br> (10x - 11)<br> (3x + 1)<br> Find the value of X
FrozenT [24]
The value of x is the meaning of the word of the value of x=14
8 0
3 years ago
The net profit in dollars per day for a small business owner is given by the equation f(x) = -0.1x^2 + 6 x + 4, where x is the n
notsponge [240]

Answer:

\large \boxed{\sf \ \ \text{The maximum profit is \$94 per day.} \ \  }

Step-by-step explanation:

Hello,

The coefficient in x^2 is negative.

So, there is a maximum at the vertex point which is

x=-\dfrac{b}{2a}==\dfrac{-6}{-0.2}=\dfrac{6}{0.2}=30

And then the maximum is f(30)=

-0.1\cdot 30^2+6\cdot 30 +4=-90 +180+4=94

So the maximum profit is 94 $ per day.

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

6 0
3 years ago
Need Help ASAP!!!!!!!!
Lady_Fox [76]

Answer:

The last one the one with (-6,00) and Range (5,00)

5 0
3 years ago
AREA ADDITION AND SUBTRACTION ASSISTANCE?
Tom [10]

The shaded area is a segment. The area of a segment is

A_{segment}=A_{sector}-A_{triangle}.

You know radius that is the side of isosceles triangle and measure of angle between two equal triangle sides, then

A_{triangle} =\dfrac{1}{2} a\cdot a \sin \alpha=\dfrac{1}{2} 18.6\cdot 18.6 \cdot  \sin 123^{\circ}=172.98\cdot  \sin 123^{\circ}=145.07 sq. m..

The area of sector is A_{sector}=\dfrac{r^2\cdot \alpha}{2}= \dfrac{(18.6)^2\cdot 0.68\pi}{2}=117.63\pi=369.53 sq. m..

Then A_{segment}=369.53-145.07=224.46 sq. m.

Answer: A_{segment}=224.46 sq. m.

7 0
4 years ago
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