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Mama L [17]
3 years ago
9

Sono Tsume Hoshi Na..

Mathematics
2 answers:
postnew [5]3 years ago
6 0

Answer:

Sono Tsume Hoshi Na..

Step-by-step explanation:

Mamont248 [21]3 years ago
3 0

Answer:

No nail for youuuuuuu

Step-by-step explanation:

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Need help with this math​
IgorLugansk [536]
<h2>Answer: 6 gallons </h2>

First we are told that we initially had 1/3 of the tank and when 10 gallons were added we had 3/4 of the tank:

\frac{1}{3}+10gallons=\frac{3}{4}    (1)

10gallons=\frac{3}{4}-\frac{1}{3}   (2)

1gallon=\frac{1}{24}    (3)

This means 1 gallon is equivalent to 1/24 tank.

On the other hand if we have 3/4 of a tank and need to reach 1 tank we have to add another fraction of the tank:

\frac{3}{4}+X=1   (4)

X=\frac{1}{4}   (5)>>>>This is the fraction needed to complete 1 tank

Now we need to know <u>how much that 1/4 tank is equivalent in gallons</u>.

From (3) we know 1gallon=\frac{1}{24} . So, we can write the following relation to transform from fractions of a tank to gallons:

\frac{1}{4}.\frac{1gallon}{\frac{1}{24}}=(\frac{1gallon}{4})(\frac{24}{1})

\frac{24}{4}gallons=6gallons

Therefore:

<h2>6 more gallons are needed to fill the tank</h2>
8 0
4 years ago
What is the answer to this problem (4+9+16/4)-8-3*5
Vikki [24]
(4+9+ \frac{16}{4} )-8-3*5= ?
Solving:
<span>First remove the parentheses:
</span>(4+9+4)-8-3*5=
17-8-3*5=
<span>First solve the multiplication:
</span>17-8-15=
<span>Do the subtraction, obeying the rule of signs of the greatest number:
</span>9-15 =
= \boxed{\boxed{-6}}\end{array}}\qquad\quad\checkmark<span>
</span>
3 0
3 years ago
Round to the nearest cent ​$73,028.85316
polet [3.4K]

Answer:

73,028.8520

pretty sure that’s what you’re asking?

3 0
4 years ago
If the sum of the interior angle measures of a polygon with n sides is 2880 find n
pshichka [43]

the sum of the interior angles in an ngon is (n-2)*180

so if the sum of the interior angles is 2880, then

2880=(n-2)*180

solve for n

divide both sides by 180

14=n-2

add 2 to both sides

16=n

n=16

4 0
3 years ago
Please help whoever can with #13 and thank you
bixtya [17]
These are so great! They are a perfect combination of Physics and pre-calculus! Your max height of that projectile is going to occur at the max value of the parabola, or at its vertex.  So we need to find the vertex.  The coordinates of the vertex will give us the x value, which is the time in seconds it takes to reach y which is the max height.  Do this by completing the square.  Begin by setting the equation equal to 0 and then moving the 80 over to the other side.  Then factor out the -16.  This is all that: -16( t^{2}-4t)=-80.  Take half the linear term which is 4 and square it and add it in to both sides.  Half of 4 is 2, 2 squared is 4, so add 4 into the set of parenthesis and to the -80.  -16( t^{2}-4t+4)=-80-64. The -64 on the right comes from the fact that when you added 4 into the parenthesis, you had the -16 out in front which is a multiplier.  -16 * 4 - -64.  So what you really added in was -64.  Now the perfect square binomial we created in that process was -16(x-2) ^{2} =-144.  When we move the 144 back over by addition we find that the vertex of the polynomial is (2, 144).  And that tells us that it takes 2 seconds for the projectile to reach its max height of 144 feet.  To find the time interval in which the object's height decreases occurs from its max height of 144 to where the graph of the parabola goes through the x-axis to the right of the max.  To find where the graph goes through the x-axis, or the zeroes of the graph, you factor the polynomial.  When you do that using the quadratic formula you get that x = -1 and 5.  So at its max height it is at 2 seconds, and by 5 seconds it hits the ground.  So the time interval of its height decreasing is from 2 seconds to 5 seconds, or a total of 3 seconds.  I think you need the 2 and 5, from the wording of your problem.
8 0
4 years ago
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