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2 years ago

Simplify 3m/m-6 * 5m^3-30m^2/5m^2

Mathematics

2 answers:

Varvara68 [4.7K]2 years ago

3 0

-30m^3-3 here is your answer

STALIN [3.7K]2 years ago

3 0

This is your answer. If you still need it:

3m/m-6 * 5m^3-30m^2/5m^2

First you need to put the numerators and the denominators together in the same "line" or "fraction if you would say.

(3m)(5m^3-30m^2)/(m-6)(5m^2)

Then you would use the distributive property and then multiply the expressions. No dividing yet.

15m^4-90m^3/5m^3-30m^2

Now you simplify with the power of exponents rule

15m-90m/5-30

Now you normally simplify by just subtracting

-75m/-25

Then simply simplify the constants

3m (The answer is 3m because -75/-25=3 positive whole numbers always stay on top [numerator], if it were negative and still on the denominator, using power of exponent rules, you would switch it up to the numerator, or "flipping" the constant or variable)

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Factorise fully the following: 4x^3+24x^2 4x^2+28x^3

prohojiy [21]

I think the answer is 4x^2 (x+6)

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3 years ago

Find the points on the ellipse 4x2 + y2 = 4 that are farthest away from the point (−1, 0).

Hitman42 [59]

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7 0

3 years ago

The perimeter of a kite is 50 mm. The length of one of its sides is 1 mm more than twice the length of another. Find the length

rosijanka [135]

Answer:

The length of the longest side is 13mm

Step-by-step explanation:

Represent the two sides with a and b, where a is the longest

$Perimeter = 50$

$a=b + 1$

Required

Determine the length of the longest side

Perimeter of a kite is calculated as thus:

$Perimeter = 2(a + b)$

Make b the subject in $a=b + 1$

$b = a -1$

Substitute a - 1 for b and 50 for Perimeter in $Perimeter = 2(a + b)$

$50 = 2(a + a - 1)$

Divide through by 2

$25 = a + a - 1$

$25 = 2a- 1$

Add 1 to both sides

$25 + 1 = 2a - 1 +1$

$25 + 1 = 2a$

$26 = 2a$

Solve for a

$a = 26/2$

$a = 13$

Hence, the length of the longest side is 13mm

4 0

2 years ago

HELP I NEED HELP ASAP

anygoal [31]

Step-by-step explanation:

Pretty sure it's A. It should be the answer

3 0

3 years ago

A person that weighs 150 pounds on earth would weigh 50 pounds on mars. how much would a person that weighs 60 pounds on earth w

Schach [20]

150 lbs on Earth is equal to 50 pounds on Mars

60 lbs on Earth is equal to _____

Set up a proportion.

$\frac{150}{50} = \frac{60}{?}$
Cross multiply.

$50 \times 60 = 3000$
$3000 \div 150 = 20$
The person would weigh 20 lbs on Mars.

3 0

3 years ago

Read 2 more answers