Answer:
a = 4.9(1 - sinθ - 0.4cosθ)
Explanation:
Really not possible without a complete setup.
I will ASSUME that this an Atwood machine with two masses (m) connected by an ideal rope passing over an ideal pulley. One mass hangs freely and the other is on a slope of angle θ to the horizontal with coefficient of friction μ. Gravity is g
F = ma
mg - mgsinθ - μmgcosθ = (m + m)a
mg(1 - sinθ - μcosθ) = 2ma
½g(1 - sinθ - μcosθ) = a
maximum acceleration is about 2.94 m/s² when θ = 0
acceleration will be zero when θ is greater than about 46.4°
Hello
I think some details of the question are missing. However, I believe you are referring to a bob following some circular path. Therefore, the answer is "no": in fact, the centripetal force is equal on the earth and on the moon.
Keep in mind that the centripetal force is given by

where m is the mass, v the tangential velocity and r the radius of the circular motion. The mass m of the bob is the same on the earth and on the moon, so the centripetal force is the same.
In order to make any conclusive diagnosis, I would need to bring Jillian
into my office, and conduct a long, slow, complete, private examination.
Where was I ?
Oh, yes.
As I started to say: Your description of Jillian's behavior is consistent
with a diagnosis of OCD.
Answer:
When object is placed between the focus (F) and pole (P) of a concave mirror, magnified and erect image of the object is formed on the back of the mirror.
When object is placed between the centre of curvature and the principal focus of a concave mirror, magnified and inverted image is formed in front of the mirror.
Explanation: