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Jobisdone [24]
3 years ago
5

Will the centripetal force on the bob be different on the moon

Physics
1 answer:
ivanzaharov [21]3 years ago
5 0
Hello
I think some details of the question are missing. However, I believe you are referring to a bob following some circular path. Therefore, the answer is "no": in fact, the centripetal force is equal on the earth and on the moon. 

Keep in mind that the centripetal force is given by
F=m \frac{v^2}{r}
where m is the mass, v the tangential velocity and r the radius of the circular motion. The mass m of the bob is the same on the earth and on the moon, so the centripetal force is the same.
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Westkost [7]

Answer:

t = 2.6 billion years

Explanation:

If potassium becomes 25% of its initial value

so we can say it becomes half two times

as we know that 25% means it is 1/4 times of initial value

so we will have

N = N_o e^{-\lambda t}

here we know that

N = 0.25 N_o

0.25 = e^{-\lmabda t}

ln 4 = (\frac{ln 2}{T_{1/2}}) t

t = 2 T_{1/2}

t = 2(1.3 billion \: years)

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4 0
3 years ago
How far will a runner travel at an average speed of 5m/s for 20 minutes?
Sonja [21]
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6 0
3 years ago
"Find the total weight of an 18-ft3 tank of oxygen if the oxygen is pressurized to 184 psia, the tank itself weighs 150 lbf, and
Fiesta28 [93]

Answer:

Explanation:

1 psi = 6894.76 Pa

P = 184 psi = 12.686 x 10⁵ Pa .

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= .51 m³

From the gas law

PV/RT = n where n is mole of gas

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= 252.78 gm mole

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= 2.20462 x 8.08896 lb

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= 17.833 / 32 lbf

= .5573 lbf

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= 150.5573 lbf .

7 0
3 years ago
PLEASE HELP!! I'll mark brainliest for correct answer.
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6 0
3 years ago
Am i correct? If not then which one
cupoosta [38]

Answer:

Yes, it's correct

Explanation:

Newton's second Law states that the acceleration of an object is proportional to the net force applied on it, according to the equation:

F=ma

where

F is the net force on the object

m is the mass of the object

a is the acceleration of the object

We can re-arrange the previous equation in order to solve explicitely for a, the acceleration, and we find:

F=ma\\\frac{F}{m}=\frac{ma}{m}\\\frac{F}{m}=a\\a=\frac{F}{m}

So, we see that the acceleration is proportional to the net force and inversely proportional to the mass of the object.

4 0
3 years ago
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