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Serggg [28]
4 years ago
11

Which is the least ...0.105 0.501 0.015 0.15

Mathematics
2 answers:
Kazeer [188]4 years ago
6 0
To figure out the least we have to look at the tenths place
(the number to the right of the decimal)
Well lets take a look
0.105
0.501
0.015
0.15 

Within the bolded numbers, which one is the least?
That would be 0.015 <- see?

So the answer is 0.015 

Good luck! :)

sergeinik [125]4 years ago
3 0
The least is 0,015

hope this will help you 
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Team A scored three times as many points as Team B. Which team scored most points? If Team A scored n point, how many points did
jonny [76]

Answer:

They scored 66 points

Step-by-step explanation:

Sally scored 45% out of the 100%

And there are 120 points in all.

To find the rest of the teams points you have to subtract Sally's points:

100% - 45% = 55

So to find this out you solve for x (points):

55/100 = x/120

100x = 6,600

100x = 6,600

100         100

x = 66

Step-by-step explanation:

4 0
2 years ago
Ben saved $66 and spent $30. What percentage of his money did he spend? Round your answer to the nearest whole percent. Can some
AleksandrR [38]

Answer:

55%

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Can someone plz help me Thank you in advance:)
yulyashka [42]

Answer : The specific heat of the metal is, 2178.67J/kg^oC

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of metal = ?

c_2 = specific heat of ice = 2000J/kg^oC

m_1 = mass of metal = 1.00 kg

m_2 = mass of ice = 1.00 kg

T_f = final temperature of mixture = -8.88^oC

T_1 = initial temperature of metal = 5.00^oC

T_2 = initial temperature of ice = -24.0^oC

Now put all the given values in the above formula, we get:

(1.00kg)\times c_1\times (-8.88-5.00)^oC=-[(1.00kg)\times 2000J/kg^oC\times (-8.88-(-24.0))^oC]

c_1=2178.67J/kg^oC

Therefore, the specific heat of the metal is, 2178.67J/kg^oC

4 0
4 years ago
The proof that ΔACB ≅ ΔECD is shown. Given: AE and DB bisect each other at C. Prove: ΔACB ≅ ΔECD Triangles A B C and C D E share
stepan [7]

Answer:

good work

Step-by-step explanation:

high

5 0
3 years ago
Read 2 more answers
What are the solutions to this equation?
ziro4ka [17]

 

\displaystyle\\(x-4)^2=49\\\\(x-4)^2-49=0\\\\(x-4)^2-7^2=0\\\\(x-4-7)(x-4+7)=0\\\\(x-11)(x+3)=0\\\\x-11 = 0~~~\text{or}~~~x+3=0\\\\x-11=0~~~\implies~~~\boxed{x_1=11}\\\\x+3=0~~~\implies~~~\boxed{x_2=-3}\\\\\boxed{\bf The~solutions~are:~~x =11~~\text{or}~~x =-3}



8 0
3 years ago
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