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natali 33 [55]
3 years ago
6

Plz, help me I will give you a brainlist and Extra points. If you help me.

Mathematics
1 answer:
stiv31 [10]3 years ago
8 0

Answer:

B) (4/9 x 20)-3

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Find the sum 7+101/2+14+.........+84​
rewona [7]

Answer: 155.5 Is your sum! (❤´艸`❤)

3 0
3 years ago
Find the vertex of the parabola formed by the following quadratic function: y = 3x^2 – 6x + 2
storchak [24]
Vertex form is y=a(x-h)^2+k, so we can rearrange to that form...

y=3x^2-6x+2  subtract 2 from both sides

y-2=3x^2-6x  divide both sides by 3

(y-2)/3=x^2-2x, halve the linear coefficient, square it, add it to both sides...in this case:  (-2/2)^2=1 so

(y-2)/3+1=x^2-2x+1  now the right side is a perfect square

(y-2+3)/3=(x-1)^2

(y+1)/3=(x-1)^2  multiply both sides by 3

y+1=3(x-1)^2  subtract 1 from both sides

y=3(x-1)^2-1  so the vertex is:

(1, -1)

...

Now if you'd like you can commit to memory the vertex point for any parabola so you don't have to do the calculations like what we did above.  The vertex of any quadratic (parabola), ax^2+bx+c is:

x= -b/(2a),   y= (4ac-b^2)/(4a)

Then you will always be able to do a quick calculation of the vertex :)
7 0
3 years ago
You launch a water balloon. The function h=-0.08t^2+1.6t+2 models the height h (in feet) of the water balloon after t seconds. W
stellarik [79]

Answer:

The initial height of the balloon is 2 feet.

Step-by-step explanation:

The height of the balloon in feet after t seconds is given by the following equation:

h(t) = -0.08t^{2} + 1.6t + 2

What is the initial height of the balloon?

This is h when t = 0, that is, h(0). So

h(0) = -0.08*0^{2} + 1.6*0 + 2 = 2

The initial height of the balloon is 2 feet.

4 0
3 years ago
Please I need help asap.
sukhopar [10]

Answer:

i cant see the question really well,can you plz send another copy

Step-by-step explanation:

8 0
2 years ago
What is 5/6 + (-4/9) - (-2)
timofeeve [1]

Answer:

2 7/18.

common denominator

8 0
3 years ago
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