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Mrrafil [7]
3 years ago
8

Can someone help me with example #1 please

Chemistry
1 answer:
Katena32 [7]3 years ago
4 0

Answer: 343 K

Explanation:

To convert Celsius to Kelvin, you would add 273 to Celsius.

70°C+273=343 K

Now, we know that 70°C is 343 K.

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WILL GIVE POINTS
Veronika [31]

Answer:A.products

Explanation:A chemical reaction is the process in which atoms present in the starting substances rearrange to give new chemical combinations present in the substances formed by the reaction. These starting substances of a chemical reaction are called the reactants, and the new substances that result are called the products.

7 0
4 years ago
t 745 K, the reaction below has an equilibrium constant (Kc) of 5.00 × 102. H2 (g) + I2 (g) ⇌ 2 HI (g) If a mixture of 0.10 mol
spayn [35]

Answer : The concentration of HI (g) at equilibrium is, 0.643 M

Explanation :

The given chemical reaction is:

                        H_2(g)+I_2(g)\rightarrow 2HI(g)

Initial conc.    0.10        0.10      0.50

At eqm.        (0.10-x)  (0.10-x)   (0.50+2x)

As we are given:

K_c=5.00\times 10^2

The expression for equilibrium constant is:

K_c=\frac{[HI]^2}{[H_2][I_2]}

Now put all the given values in this expression, we get:

5.00\times 10^2=\frac{(0.50+2x)^2}{(0.10-x)\times (0.10-x)}

x = 0.0713  and x = 0.134

We are neglecting value of x = 0.134 because the equilibrium concentration can not be more than initial concentration.

Thus, we are taking value of x = 0.0713

The concentration of HI (g) at equilibrium = (0.50+2x) = [0.50+2(0.0713)] = 0.643 M

Thus, the concentration of HI (g) at equilibrium is, 0.643 M

8 0
4 years ago
Substrate: N-benzoyl-L-tyrosine ethyl ester (BTEE) 0.001M
Anna71 [15]

Based on the dilution formula, 0.1 mL of the stock solution of the enzyme is required to prepare a 50-fold diluted enzyme in 0.01 M HCl.

<h3>How can 50-fold dilution of the enzyme be done?</h3>

The 50-fold dilution of the stock enzyme solution can be done by using the dilution formula to determine the given volume of the stock solution required.

The dilution formula is given below:

  • C1V1 = C2V2

where:

  • C1 = Initial concentration of enzyme
  • C2 = Final concentration of enzyme
  • V1 = Initial volume
  • V2 = Final volume

From the given data for the enzyme dilution;

C1 = 1

C2 = 1/50 = 0.02

V1 = x

V2 = 5 ml

Making V1 subject of formula in the dilution formula:

V1 = C2V2/C1

V1 =  0.02 * 5/1 = 0.1 mL

Therefore, 0.1 mL of the stock solution of the enzyme is required to prepare a 50-fold diluted enzyme in 0.01 M HCl.

Learn more about dilution at: brainly.com/question/24709069

#SPJ1

7 0
2 years ago
A student carried out this reaction with methane as the limiting reagent. A 12.0 g quantity of methane was used, and the student
Sophie [7]

Answer:

The percent yield is 66.7%

Explanation:

1. The balanced chemical reaction to obtain carbon dioxide from the methane is:

CH_{4}+2O_{2}=CO_{2}+2H_{2}O

2. Calculathe the theoretical quantity of carbon dioxide.

As the problem says that the limiting reagent is the methane, all the calculations will be made from this quantity:

12.0gCH_{4}*\frac{1molCH_{4}}{16gCH_{4}}*\frac{1molCO_{2}}{1molCH_{4}}*\frac{44gCO_{2}}{1molCO_{2}}=33gCO_{2}

3. Calculate the percent yield:

Percent yield = \frac{actualyield}{theoreticalyield}*100

Percent yield = \frac{22.0g}{33.0g}*100

Percent yield = 66.7%

7 0
3 years ago
HELP PRETTY PLEASE QUICKLY!!! AND ILL GIVE YOU BRAINLIEST
Yuri [45]

Answer: The answer is C

Explanation: Sound waves tend to spread farther the deeper the sound is, and the waves go lower then the second example, deeming it is louder.

8 0
3 years ago
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