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RSB [31]
3 years ago
12

What is going to happen to a balloon filled with helium that is left in a car over night when the temperature drops approximatel

y 20 degrees
Chemistry
1 answer:
Scilla [17]3 years ago
6 0

Answer:

<u><em>When balloon filled with the helium gas is left in the car at night along with the decrease in temperature the size of the balloon will get smaller or it will look like little deflated</em></u>.The above observation can be explained on the basis of Charles law:The law states that 'under constant pressure ,the volume occupied by the gas is directly proportional to the temperature of the gas'. (At constant pressure)Temperature desecrate volume will also decreases and vice versa.So, with decrease in temperature at night the temperature of the gas in the balloon will also get decreased due to which the volume of the balloon will also get decreased.

Explanation:

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Which half-reaction correctly represents reduction?
Gemiola [76]
Answer choice C. Reduction has its electrons as a reactant.
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A 0.539 g sample of a metal, M, reacts completely with sulfuric acid according to the reaction M(s)+H2SO4(aq)⟶MSO4(aq)+H2(g) A v
Charra [1.4K]

Answer:

The molar mass of the metal is 54.9 g/mol.

Explanation:

When we work with gases collected over water, the total pressure (atmospheric pressure) is equal to the sum of the vapor pressure of water and the pressure of the gas.

Patm = Pwater + PH₂

PH₂ = Patm - Pwater = 1.0079 bar - 0.03167 bar = 0.9762 bar

The pressure of H₂ is:

0.9762bar.\frac{1atm}{1.013bar} =0.9637atm

The absolute temperature is:

K = °C + 273 = 25°C + 273 = 298 K

We can calculate the moles of H₂ using the ideal gas equation.

P.V=n.R.T\\n=\frac{P.V}{R.T} =\frac{0.9637atm \times 0.249L }{(0.08206atm.L/mol.K)\times298K} =9.81 \times 10^{-3} mol

Let's consider the following balanced equation.

M(s) + H₂SO₄(aq) ⟶ MSO₄(aq) + H₂(g)

The molar ratio of M:H₂ is 1:1. So, 9.81  × 10⁻³ moles of M reacted. The molar mass of the metal is:

\frac{0.539g}{9.81 \times 10^{-3} mol} =54.9g/mol

4 0
3 years ago
2. Which of the following is true about the total number of reactants and the total number of
Soloha48 [4]

9 moles of reactants chemically change into 11 moles of product.

Explanation:

In the reaction above, 9 moles of reactants chemically change into 11 mole of products. The coefficients in a reaction is the number of moles of the reacting atoms .

  • For example 8O₂ depicts 8 moles of two oxygen atoms.
  • The number of moles  is a unit for quantifying particles.
  • You can liken it to a dozen, gross or a score.
  • Since a mole of a substance contains avogadro number of particles. We can relate the number of moles to other parameters.

Learn more:

Moles brainly.com/question/2272966

#learnwithBrainly

8 0
2 years ago
Read 2 more answers
In this experiment, student groups ran repeated trials (5) and then averaged their data. ALL BUT ONE statement explains why
Colt1911 [192]

Answer:

its B

Explanation:

trust me i had this in my usatestprep, also follow me on tiktok, its ultrasolos

3 0
3 years ago
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A sample of solid sodium hydroxide, weighing 13.20 grams is dissolved in deionized water to make a solution. What volume in mL o
Andreas93 [3]
<h3>Answer:</h3>

2.809 L of H₂SO₄

<h3>Explanation:</h3>

Concept tested: Moles and Molarity

In this case we are give;

Mass of solid sodium hydroxide as 13.20 g

Molarity of H₂SO₄ as 0.235 M

We are required to determine the volume of H₂SO₄ required

<h3>First: We need to write the balanced equation for the reaction.</h3>
  • The reaction between NaOH and H₂SO₄ is a neutralization reaction.
  • The balanced equation for the reaction is;

2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O

<h3>Second: We calculate the umber of moles of NaOH used </h3>
  • Number of moles = Mass ÷ Molar mass
  • Molar mass of NaOH is 40.0 g/mol
  • Therefore;

Moles of NaOH = 13.20 g ÷ 40.0 g/mol

                          = 0.33 moles

<h3>Third: Determine the number of moles of the acid, H₂SO₄</h3>
  • From the equation, 2 moles of NaOH reacts with 1 mole of H₂SO₄
  • Therefore, the mole ratio of NaOH: H₂SO₄ is 2 : 1.
  • Thus, Moles of H₂SO₄ = moles of NaOH × 2

                                    = 0.33 moles × 2

                                   = 0.66 moles of H₂SO₄

<h3>Fourth: Determine the Volume of the acid, H₂SO₄ used</h3>
  • When given the molarity of an acid and the number of moles we can calculate the volume of the acid.
  • That is; Volume = Number of moles ÷ Molarity

In this case;

Volume of the acid = 0.66 moles ÷ 0.235 M

                                = 2.809 L

Therefore, the volume of the acid required to neutralize the base,NaOH is 2.809 L.

7 0
3 years ago
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