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Vlada [557]
3 years ago
11

Bee humming birds weigh only 0.0056 ounces. They haev t eat half their body weight every day to survive. How much food does a be

e humming bird have to each day
Mathematics
1 answer:
Advocard [28]3 years ago
5 0

Answer:

The Humming bee need to eat 0.0028 ounces of food each day.

Step-by-step explanation:

Given:

Weight of the humming bee = 0.0056 ounces

We need to find amount of food humming bee should eat each day to survive.

Solution:

Now given that:

They have to eat half their body weight every day to survive.

So we can say that;

Amount of food humming bee needs to eat is half of the weight of the humming bee.

framing in equation form we get;

Amount of food humming bee needs to eat  = \frac{1}{2}\times 0.0056 =  0.0028\ ounces

Hence The Humming bee need to eat 0.0028 ounces of food each day.

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An engineer is designing an arch-shaped gate for the entrance to an amusement park. The gate must be 80 feet wide and 25 feet ta
Tom [10]
1) the form of the equation may be written as y = A(X - Xo)(X - X1)

Where Xo and X1 are the two roots of the equation.


2) We can fix the system of coordinates so that the vertex is in the middle of the gate => Xo = - 40 and X1 = +40


=> y = A (X + 40) (X - 40) = A (X^2 - 1600) 


3) The height, at X = 0 is 25

=> A(0 - 1600) = 25


=> -1600A = 25 => A = -25 / 1600 = - 1/64


4) The equation is y =  - [1/64] (X^2 - 1600)


5) You can present it in different equivalent forms.

Some of those other forms are:

1) - 64y = (x^2 - 1600)

2) x^2 = - 64y + 1600

3) X^2 = - 64 (y - 25)
4 0
3 years ago
A production process produces 2% defective parts. a sample of 5 parts from the production is selected. what is the probability t
Lana71 [14]

Answer:

Probability of a sample that contains exactly two defective parts is .0037 or .37%

Step-by-step explanation:

As we know if P is the probability of achieving k results in n trials then probability formula is P = \binom{n}{k}p^{K}q^{n-k}

In this formula n = number of trials

                        k = number of success

                        (n-k) = number of failures

                         p = probability of success in one trial

                         q = (1-p) = probability of failure in one trial

In this sum n = 5

                  k = 2

number failures (n-k) = (5-2) = 3

                            p = 2% which can be written as .02

                            q = 98% Which can be written as .98

Now putting these values in the formula

                        P = \binom{5}{2}(.02)^{2}(.98)^{5-2}

                        P = \binom{5}{2}(.02)^{2}(.98)^{3}

                   \binom{5}{2}= 5!/3!2!    

                                              = 5×4×3×2×1/3×2×1×2×1

                                              = 5×2 =10

                                       P = 10×(.02)²×(.98)³

                                          = .0037 or .37%

4 0
3 years ago
Read 2 more answers
One fourth of a number is 1 more than one fifth of the same number
Arlecino [84]
The most important part of this question is understanding the words of the problem. The trick lies in the words of the problem. Once the web of words is simplified, the problem becomes very easy. The main thing is converting the words into numbers.
Let us assume the unknown number = x
Then from the question we get
(x/4) = (x/5) + 1
(x/4) - (x/5) = 1
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x/20 = 1
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3 years ago
What is (6^3 - 9 - 1)​
Vika [28.1K]
That answer would be 206
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2 years ago
Is 40,100 divisible by 10?
ozzi

Answer:

C

Step-by-step explanation:

Any number with a 0 at the end is divisible by 10

7 0
3 years ago
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