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xenn [34]
3 years ago
7

Let 2 × 2 × 2 = n. Which choice also equals n?

Mathematics
1 answer:
weeeeeb [17]3 years ago
3 0
I'm guessing B is supposed to be 2^3. So, it would be B.
You might be interested in
If the mean of 2 3 x and 5 is 4,find x​
Alchen [17]

Answer:

the missing number is 6

Step-by-step explanation:

To find the mean, add up all the numbers and divide by the number of numbers

( 2+3+x+5) /4 = 4

Combine like terms

(10+x)/4 =4

Multiply each side by 4

10+x = 16

Subtract 10 from each side

x = 6

3 0
3 years ago
A square pyramid has a base area of 64 ft2. The pyramid’s total surface area is 224 ft2.
borishaifa [10]

The area of each triangular face is 40 square feet

<em><u>Solution:</u></em>

Given that,

Square pyramid has a base area of 64 square feet

The pyramid’s total surface area is 224 square feet

The total surface area of a regular pyramid is the sum of the areas of its lateral faces and its base

<em><u>Therefore, total surface area of square pyramid is given as,</u></em>

Total surface area = base area + 4(Area of traingular face)

Let "x" be the area of each traingular face

224 = 64 + 4(x)\\\\224 - 64 = 4x\\\\4x = 160\\\\x = 40

Thus area of each triangular face is 40 square feet

5 0
3 years ago
The quotient of 20 and 3 more than x is 4. Find x.
tigry1 [53]

Answer:

x=2

Step-by-step explanation:

Quotient means division

20/(x+3) =4

Multiply each side by (x+3)

(x+3)*20/(x+3) =4(x+3)

20 = 4(x+3)

Divide each side by 4

20/4 = 4(x+3)/4

5 = x+3

Subtract 3 from each side

5-3 = x+3-3

2 =x

4 0
3 years ago
Read 2 more answers
Two airplanes leave an airport at the same time, the first headed due north and the second at a bearing of N42^ E . At 2:00PM, t
Leno4ka [110]

Answer:

The two airplanes are about 330miles apart.

Step-by-step explanation:

The diagram interpreting the question has been attached to this response.

As shown in the diagram,

i. the airplanes leave at point C.

ii. at 2.00pm the first and second airplanes are at points A and B respectively, where they are 312miles and 487miles away from the starting point C in directions due north and N42E from the point C.

iii. the points A, B and C form a triangle with sides a, b and c.

To solve for the value of c which is the distance between the two planes at 2.00pm, the cosine rule is used.

c² = a² + b² - 2abcosC            --------------(i)

where;

b  = 312miles

a = 487miles

C = 42°

Substitute these values into equation (i) and solve as follows;

c² = (487)² + (312)² - 2(312)(487)cos(42)

c² = (237169) + (97344) - 303888cos(42)

c² = (237169) + (97344) - 303888(0.7431)

c² = 334513 - 225819.1728

c² = 108693.8272

<em>Take the square root of both sides</em>

√c² = √108693.8272

c = 329.69

c ≅ 330miles

Therefore, the two airplanes are far apart by 330miles

3 0
3 years ago
Mr Ordonez gives his math students 34 quizzes during 17 weeks of school. If he gave the same number of quizzes each week, how ma
meriva
2.

Using division we get
34/17= 2
8 0
3 years ago
Read 2 more answers
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