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3 years ago

Solve logx + log(x-3) = 1

Mathematics

1 answer:

yaroslaw [1]3 years ago

8 0

=log10x(x-3)=1
=x(x-3)=10
=x^2-3x=10
Make this a quadratic equation
x^2-3x-10=0
Factorize
=(x+2)(x-5)=0
x=-2 or x=5

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If the square root of 1 over 2 x - 10 added by 3, which inequality can be used to find the domain of f(x)?

jeyben [28]

From the description, we have the function $f(x)= \sqrt{ \frac{1}{2x-10}+3 }$
Since the square root cannot be a negative number, the only thing need to do to find the domain of the function $f(x)$ is take the expression inside the square rot and set it greater or equal than zero:
$\frac{1}{2x-10}+3 \geq 0$
$\frac{6x-29}{2x-10} \geq 0$
$\frac{6x-29}{2(x-5)} \geq 0$
$x \leq \frac{29}{6}$ or $x\ \textgreater \ 5$

We can conclude that we can use the inequality $\frac{1}{2x-10}+3 \geq 0$ to find the domain of $f(x)$ . Also, the domain of $f(x)$ is (∞, $\frac{29}{6}$ ]U(5,∞).

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4 years ago

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Answer:

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Step-by-step explanation:

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I hope this helps :))

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3 years ago

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Alborosie

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Step-by-step explanation:

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3 years ago

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vazorg [7]

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3 years ago

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Answer:

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3 years ago

Read 2 more answers