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kvv77 [185]
3 years ago
7

It's in the picture ?

Mathematics
1 answer:
nignag [31]3 years ago
4 0

Answer:

<h2>4</h2>

Step-by-step explanation:

From first piece -6 < x ≤ 0.

From second piece 0 < x ≤ 4.

Therefore -6 < x ≤ 4 → x ∈ (-6, 4]

-7 ∉ (-6, 4]

-6 ∉ (-6, 4]

4 ∈ (-6, 4]

5 ∉ (-6, 4]

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13. The photo below is being enlarged to form a 24-by 30-inch print. What is the scale factor being used to enlarge it?​
RUDIKE [14]

Answer:

6

Step-by-step explanation:

24/4 = 6

30/5 = 6

Dividing the values of the larger print by the corresponding values of the smaller print results in a scale factor of 6

5 0
2 years ago
Original Price:<br> $25.00<br> Take 10% off,<br> and then take<br> $1.00 off that<br> amount:
JulsSmile [24]

Answer:

25 times .10 = 2.5 (22.5) 22.5-1.00= 21.5

Step-by-step explanation:

7 0
3 years ago
List the single-digit divisors of 2100.<br> I really need help
liberstina [14]

Answer:

  • 1, 2, 3, 4, 5, 6, 7

Step-by-step explanation:

<u>Prime factors of 2100 are:</u>

  • 2100 = 2*2*3*5*5*7

<u>The single-digit divisors are:</u>

  • 1, 2, 3, 2*2= 4, 5, 2*3= 6, 7

-----------------------------------------------------------------

<u>Another solution is you divide 2100 by all numbers 1 through 9 and list those divisible:</u>

  • 2100/1 = 2100, yes
  • 2100/2 = 1050, yes
  • 2100/3 = 700, yes
  • 2100/4 = 525, yes
  • 2100/5 = 420, yes
  • 2100/6 = 350, yes
  • 2100/7 = 300, yes
  • 2100/8 = 262.5, no
  • 2100/9 = 233.33, no

So all the numbers from 1 to 7

5 0
3 years ago
What is the distance between -10 and six on a number line
Mkey [24]

Answer:

10+6=16

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
The 17th term of an Arithmetic sequence is 51. If the commons difference is 7, what is the first term ?
vovikov84 [41]

Answer:

The first term is:

  • a_1=-61

Step-by-step explanation:

The arithmetic sequence is defined by

a_n=a_1+\left(n-1\right)d

where

a_1 is the first term

d is the common difference

as

the 17th term of an arithmetic sequence is 51.

i.e. a_{17}=51

so

a_n=a_1+\left(n-1\right)d

a_{17}=a_1+\left(17-1\right)d        

51=a_1+\left(17-1\right)7         ∵ n = 17, a_{17}=51 , d=7

a_1+112=51                   ∵ \left(17-1\right)\cdot \:\:7=112

a_1=-61

Therefore, the first term is:

  • a_1=-61
8 0
3 years ago
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