Pls answer fast. will give brainliest (v2)
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The rule for expressing a radical as a rational exponent is as follows:
![\sqrt[n]{x^y} = x^ \frac{y}{n}](https://tex.z-dn.net/?f=%20%5Csqrt%5Bn%5D%7Bx%5Ey%7D%20%3D%20x%5E%20%5Cfrac%7By%7D%7Bn%7D%20)
So, to find![\sqrt[3]{27x^2y^3z^4}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B27x%5E2y%5E3z%5E4%7D%20%20)
use that rule.
The cube root of 27 is 3, so the equation will start with 3.
Hope that helps!
So, to find
The cube root of 27 is 3, so the equation will start with 3.
Hope that helps!