The projection of 
onto 
is
We have
X^2 + y^2 - 2x + 7y + 1 = 0
(x^2 - 2x) + (y^2 + 7y) + 1 = 0
(x^2 - 2x + 1) + (y^2 + 7y) + 1 = 0+1
(x^2 - 2x + 1) + (y^2 + 7y + 49/4) + 1 = 0+1+49/4
(x - 1)^2 + (y + 7/2)^2 + 1 = 0+1+49/4
(x - 1)^2 + (y + 7/2)^2 + 1-1 = 0+1+49/4-1
(x - 1)^2 + (y + 7/2)^2 = 49/4
(x - 1)^2 + (y + 7/2)^2 = (7/2)^2
The final answer is choice B
Answer:
x>7 or x<1
Step-by-step explanation:
Either 2x-8>6 or 2x-8<-6
Possiblity #1
2x-8>6
Add 8 to both sides
2x>14
Divide both sides by 2
Get x>7
Possibility #2
2-8>-6
Add 8 to both sides
2x<2
Divide both sides by 2
x<1
Answer
42
Step-by-step explanation:
The area of a triangle is "triangle = BxH" Which in your case is 6x7
