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Ira Lisetskai [31]
4 years ago
5

Two thirds of my cats plus five

Mathematics
1 answer:
Ad libitum [116K]4 years ago
6 0
2/3+5...add both numbers and this is what you have=17/3

You might be interested in
Small notebooks cost $3.50 and large notebooks cost $5.00. She needs to buy 31 notebooks, and she has $134 to spend. How many sm
Darina [25.2K]

Let's assume

number of small notebooks =x

number of large notebooks =y

we are given

total number of notebooks =31

so, we get

x+y=31

now, we can solve for y

y=31-x

we have

Small notebooks cost $3.50 and large notebooks cost $5.00

she has $134 to spend

so, we get

3.50x+5y=134

now, we can plug y

3.50x+5(31-x)=134

3.50x+5*31-5x=134

-1.5x+155=134

-1.5x+155-155=134-155

x=14

now, we can find y

y=31-14

y=17

so,

number of small notebooks is 14

number of large notebooks is 17.............Answer


6 0
3 years ago
Read 2 more answers
Find the length of YZ
emmainna [20.7K]
Larger triangle’s base length

a^2 + b^2 = c^2
a^2 + 3^2 = 8^2
a^2 = 8^2 - (3^2)
sqrt(a^2) = sqrt(55)
a = sqrt(55)
__________________

Smaller triangle’s base length:

The same formula applies.
a^2 + 3^2 = 5^2
a^2 = 5^2 - (3^2)
sqrt(a^2) = sqrt(16)
a = 4
____________

The finale!

Add the two side lengths of a, which is sqrt(55) + 4 (exact answer)
or... 11.416 (unrounded to thousandths place)

Good luck to you!
5 0
3 years ago
2. A man buys eggs at 55kobo a score . he finds that 10% of the eggs are unsellable but sells the rest at 60kobo a dozen .find i
liubo4ka [24]

Answer:

Percentage Profit is 63.63%

Step-by-step explanation:

The man buys 440 eggs at 55 pence a score

i.e. he buys 20 eggs for 55 pence

He buys 1 egg for 55/20 = 2.75 pence

Therefore, he buys 440 eggs for = 440 × 2.75 = 1210 pence

10% eggs are unsaleable

thus he sold = 440 - 440 × 10/100 = 440 - 44 = 396 eggs

Eggs sold in dozen = 396/12 = 33

He sold 1 dozen for = 60 pence

Thus, he sold 33 dozen for = 33 × 60 = 1980 pence

Profit = 1980 - 1210 = 770 pence

% Profit = (770/1210) × 100 = 63.63%

(hope this helps can i plz have brainlist :D hehe)

3 0
3 years ago
Consider the equation.
babunello [35]

Answer:

If you use the addition property of equality, what number would you add to both sides of the equal sign to isolate the variable?

You would subtract 5/7 from both sides of the equation

What is the solution?

x = 26/7 or 3 and 5/7

Step-by-step explanation:

x + 5/7 = 31/7

Subtract 5/7 from both sides of the equation:

x + 5/7 - 5/7 = 31/7 - 5/7

x = 26/7

6 0
3 years ago
Read 2 more answers
Find the sumofthe geometrical progression of five terms, of which the first term is 7 and the multiplier is 7.Verify that the su
777dan777 [17]

Answer:

The sum of first five term of GP is 19607.

Step-by-step explanation:

We are given the following in the question:

A geometric progression with 7 as the first term and 7 as the common ration.

a, ar, ar^2,...\\a  = 7\\r = 7

7, 7^2, 7^3, 7^4...

Sum of n terms in a geometric progression:

S_n = \displaystyle\frac{a(r^n - 1)}{(r-1)}

For sum of five terms, we put n= 5, a = 7, r = 7

S_5 = \displaystyle\frac{7(7^5 - 1)}{(7-1)}\\\\S_5 = 19607

The sum of first five term of GP is 19607.

Verification:

2801\times 7 = 19607

Thus, the sum is equal to product of 2801 and 7.

7 0
3 years ago
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