The answer would be 10 degrees
i hope this helps
Answer:
<h2>A. (0,1)</h2>
Step-by-step explanation:
The question lacks the e=required option. Find the complete question below with options.
Which of the following points does not belong to the quadratic function
f(x) = 1-x²?
a.(0,1) b.(1,0) c.(-1,0)
Let f(x) = 0
The equation becomes 1-x² = 0
Solving 1-x² = 0 for x;
subtract 1 from both sides;
1-x²-1 = 0-1
-x² = -1
multiply both sides by minus sign
-(-x²) = -(-1)
x² = 1
take square root of both sides;
√x² = ±√1
x = ±1
x = 1 and x = -1
when x = 1
f(x) = y = 1-1²
y = 1-1
y = 0
when x = -1
f(x) = y = 1-(-1)²
y = 1-1
y = 0
Hence the coordinate of the function f(x) = 1-x² are (±1, 0) i.e (1, 0) and (-1, 0). The point that does not belong to the quadratic function is (0, 1)
Answer:
5x2x6
Step-by-step explanation:
Because you cut it in half so you have to divide the length and width by 2.
The answer is 7R5. Definitely
Answer:
4w + 9
Step-by-step explanation:
Area of rectangle = length x width (or base x height, depending on how you look at it).
It is given to you that:
Area = 8w + 18
Length = 2
Let: width = x
Plug in the corresponding terms with the corresponding words:
8w + 18 = 2x
Isolate the variable, x. Divide 2 from both sides of the equation:
(8w + 18)/2 = (2x)/2
x = (8w + 18)/2
w = (8w)/2 + (18)/2
w = 4w + 9
4w + 9 is the expression that represents the width of the rectangle.
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