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stellarik [79]
3 years ago
15

What is 4(2y+5) + (-6-4y)

Mathematics
1 answer:
zvonat [6]3 years ago
4 0
The answer is 6(4y-1)
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Drag each length to the correct location on the image. Each length can be used more than once, but not all lengths will be used.
RSB [31]

Answer:

The length of the unknown sides of the triangles are as follows:

CD = 10√2

AC = 10√2

BC =  10

AB = 10

ΔACD is a right angle triangle. Therefore, Pythagoras theorem can be used to find the sides of the triangle.

c² = a² + b²

where

c = hypotenuse side = AD = 20

a and b are the other 2 legs

lets use trigonometric ratio to find CD,

cos 45 = adjacent / hypotenuse

cos 45 = CD / 20

CD = 1 / √2 × 20

CD = 20 / √2 = 20√2 / 2 = 10√2

20² - (10√2)² = AC²

400 - 100(2)  = AC²

AC² = 200

AC = √200 = 10√2

ΔABC is a right angle triangle too. Therefore,

AB² + BC² = AC²

Using trigonometric ratio,

cos 45 = BC / 10√2

BC = 10√2 × cos 45

BC = 10√2 × 1 / √2

BC = 10√2 / √2 =  10

(10√2)² - 10² = AB²

200 - 100 = AB²

AB² = 100

AB = 10

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Will give brainliest
Verdich [7]
I believe the correct answer is D
5 0
3 years ago
IGNOR MY ANSWER I ALSO NEED TO KNOW IF IT'S OPEND OR CLOSED Graph the solution to this inequality on the number line.
Alex777 [14]

Answer:

open circle

Step-by-step explanation:

\leq \geq = closed cirle\\ =open circle

6 0
2 years ago
Evaluate 2/3x for x = 3/4. Please show your work.<br> Thank you!!! :)
GenaCL600 [577]
X = 3/4
So substitute x for 3/4 in <span> 2/3x
(3/4) x (2/3)

Now solve
</span>(3/4) x (2/3) = 1/2 or 0.5

5 0
2 years ago
syeda has finished 20% of her math assignment. The assignment includes 50 problems how many problems has syeda completed?
Nostrana [21]

Answer:

10 problems

Step-by-step explanation:

This is the answer because:

1) We have to solve for what 20% of 50 is since she finished 20% of her test:

20% of 50 = 10

\frac{2}{10} × \frac{50}{1} = \frac{100}{10} = 10

Therefore, the answer is 10 problems.

Hope this helps! :D

5 0
3 years ago
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