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2 years ago

- 2/3x=6 Solve for X

Mathematics

2 answers:

chubhunter [2.5K]2 years ago

7 0

Answer: -9

Step-by-step explanation: In this equation, notice that x is being multiplied by a fraction. In this situation, in order to get x by itself, we must multiply both sides of the equation by the reciprocal of that fraction.

The reciprocal of a fraction is just that fraction flipped so the reciprocal of -2/3 is just -3/2. So here, in order to get x by itself, we multiply both sides of the equation by -3/2.

On the left, our 3's cancel and our 2's cancel and we have x. On the right our 6 and 2 reduced to 3 and 1 so we have 3 x -3 which is -9

Now we have x = -9.

BartSMP [9]2 years ago

6 0

Answer:

Step-by-step explanation:

-9

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2 years ago

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Soloha48 [4]

Answer:

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Step-by-step explanation:

Given

$\sqrt[3]{217}$

Required

Solve

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$f(x + \triangle x) \approx f(x) +\triangle x \cdot f'(x)$

Take:

$x = 216; \triangle x= 1$

So:

$f(x) = \sqrt[3]{x}$

Substitute 216 for x

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So, we have:

$f(x + \triangle x) \approx f(x) +\triangle x \cdot f'(x)$

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$f(216) \approx 6 +1 \cdot f'(x)$

To calculate f'(x);

We have:

$f(x) = \sqrt[3]{x}$

Rewrite as:

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Split

$f'(x) = \frac{1}{3} \cdot \frac{x^\frac{1}{3}}{x}$

$f'(x) = \frac{x^\frac{1}{3}}{3x}$

Substitute 216 for x

$f'(216) = \frac{216^\frac{1}{3}}{3*216}$

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$f'(216) = \frac{3}{324}$

So:

$f(216) \approx 6 +1 \cdot f'(x)$

$f(216) \approx 6 +1 \cdot \frac{3}{324}$

$f(216) \approx 6 + \frac{3}{324}$

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