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iren [92.7K]
3 years ago
7

Which variable is most important to the following problem? At 9:00 a.m., a wind speed of 20 miles per hour was recorded. After t

hat, the wind speed was recorded every hour. Each measurement showed an increase in wind speed of 3 miles per hour. The strongest wind was recorded at 4:00 p.m. After that, the wind speeds started to decrease. What was the top wind speed? A. the time of day the first measurement was made B. the miles-per-hour speed of the wind at its maximum point C. the number of hours it took for the wind speed to reach its minimum for the day
Mathematics
2 answers:
slavikrds [6]3 years ago
8 0

Answer:

option-C

Step-by-step explanation:

We are given

At 9:00 a.m., a wind speed of 20 miles per hour was recorded

So, initial wind speed =20 miles per hour

Each measurement showed an increase in wind speed of 3 miles per hour

The strongest wind was recorded at 4:00 p.m

so,

top wind speed = initial wind speed + ( total number of hours between 9:00 am and  4:00 pm)*(change in wind speed)

top wind speed = 20 mph+(16-9)*3

=20+7\times 3

=41 miles per hour

Since, change in wind speed and initial wind speed are constant

but the number of hours it took for the wind speed to reach its minimum for the day can be changed

so, most important variables is

the number of hours it took for the wind speed to reach its minimum for the day can be changed

sladkih [1.3K]3 years ago
5 0

Answer:

The answer is B. The miles per hour speed of the wind at its maximum point

explanation:

apex

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Before building the confidence interval, we need to understand the central limit theorem and subtraction between normal variables.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

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The 95% confidence interval for the difference in the proportion of cancer diagnoses between the two groups is (0.3834, 0.5166).

3 0
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Answer:

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