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PtichkaEL [24]
3 years ago
5

A lost turtle - swimming 13 feet below the surface of the water - begins to ascend at 0.5 foot per second. In hopes of (harmless

ly) capturing the turtle, a diver jumps into the water to a depth of 4 feet before descending at a rate of 0.25 foot per second.
a) Write an equation to model the position of the turtle at any given time.



b) Write an equation to model the position of the diver at any given time.



c) After how long will the diver be able to catch the turtle?



d) At what depth will the diver be able to catch the turtle?
Mathematics
2 answers:
Ilia_Sergeevich [38]3 years ago
7 0

Answer:

(0.25-13) 0.5

Step-by-step explanation:

Black_prince [1.1K]3 years ago
5 0

Answer:

16(-18)

Step-by-step explanation:

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nikitadnepr [17]

Answer:

f(N) = 2+ N/2 + 6N² units of time.

Step-by-step explanation:

Assigning 0 to the variable sum takes one unit of time.

Each time you increment sum by B, you need to call the value of sum, sum it to B and assign it to sum, which takes three units of time in total. You are repeating this process for each value of B which ranges from 1 to 4n and for each value of A which ranges from 1 to n/2. Opening the FOR takes also another unit of time, so, as a result, we have

f(N) 1 + 1 (open the FOR in A)+ N/2*(1 (open the FOR in B) + 4N*3) = 2+ N/2 + 6N² units of time. It has order complexity O(N²).

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4 years ago
In simplest radical form, what are the solutions to the quadratic equation 6 = x2 - 10x?
WARRIOR [948]

Answer:

x = 5 - \sqrt{31}, 5 + \sqrt{31}

Step-by-step explanation:

6 = x^2 - 10x

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Let's use the quadratic formula. ( x = \frac{-b +- \sqrt{b^2 - 4ac}}{2a})

x = \frac{10 +- \sqrt{-10^2 - 4(-6)}}{2}

x = \frac{10 +- 2\sqrt{31} }{2}

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Answer:

387 km

Step-by-step explanation:

The length of AC, b can be obtained using the cosine rule ; using the cosine relation:

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