X= -1,0,2,2. y=10,15,28,49

Pls help dont care about the blue dot btw

alexdok [17]

Answer:

the answer is B

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

The hourly median power (in decibels) of received radio signals transmitted between two cities

trasher [3.6K]

Using the lognormal and the binomial distributions, it is found that:

The 90th percentile of this distribution is of 136 dB.

There is a 0.9147 = 91.47% probability that received power for one of these radio signals is less than 150 decibels.

There is a 0.0065 = 0.65% probability that for 6 of these signals, the received power is less than 150 decibels.

In a lognormal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{\ln{X} - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.

After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

In this problem:

The mean is of $\mu = 3.5$ .

The standard deviation is of $\sigma = \sqrt{1.22}$

Question 1:

The 90th percentile is X when Z has a p-value of 0.9, hence X when Z = 1.28.

$Z = \frac{\ln{X} - \mu}{\sigma}$

$1.28 = \frac{\ln{X} - 3.5}{\sqrt{1.22}}$

$\ln{X} - 3.5 = 1.28\sqrt{1.22}$

$\ln{X} = 1.28\sqrt{1.22} + 3.5$

$e^{\ln{X}} = e^{1.28\sqrt{1.22} + 3.5}$

$X = 136$

The 90th percentile of this distribution is of 136 dB.

Question 2:

The probability is the p-value of Z when X = 150, hence:

$Z = \frac{\ln{X} - \mu}{\sigma}$

$Z = \frac{\ln{150} - 3.5}{\sqrt{1.22}}$

$Z = 1.37$

$Z = 1.37$ has a p-value of 0.9147.

There is a 0.9147 = 91.47% probability that received power for one of these radio signals is less than 150 decibels.

Question 3:

10 signals, hence, the binomial distribution is used.

Binomial probability distribution

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

n is the number of trials.

p is the probability of a success on a single trial.

For this problem, we have that $p = 0.9147, n = 10$ , and we want to find P(X = 6), then:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 6) = C_{10,6}.(0.9147)^{6}.(0.0853)^{4} = 0.0065$

There is a 0.0065 = 0.65% probability that for 6 of these signals, the received power is less than 150 decibels.

You can learn more about the binomial distribution at brainly.com/question/24863377

5 0

3 years ago

Lindsay enjoys looking at the different coins people have thrown into the fountain at the mall. Which statement best explains ho

Nina [5.8K]

Answer: Electrons in water act in a similar way to visible light so they don't absorb or reflect most of the light. Instead they allow it to pass through relatively unimpeded, absorbing wavelengths like infrared and reflecting invisible UV

7 0

3 years ago

Find (f-g)(x) for the following functions. f(x) = 12x + 20 g(x) = –11x2 + 10x + 33

IRINA_888 [86]

Answer:

11x2 + 2x-13

Step-by-step explanation:

We must build the new function f-g, which turns to be a sum between polynomials.

f(x)-g(x)= 12x+20 + 11x2- 10x-33

f(x)-g(x)= 11x2 + 2x-13

3 0

3 years ago

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Two boys decided to buy a computer. The second boy had 5/6 of the money the first had. The first boy had 7/8 of the price of the

UNO [17]

Answer:

The price of the computer is $1,152

Step-by-step explanation:

Let the price of the computer be $x

The first boy boy had 7/8 of this amount, the amount he has is thus 7/8 × $x = 7x/8

The second boy had 5/6 of what the first boy had. The amount of money he has is thus 5/6 × 7x/8 = 35x/48

Now, the addition of what they have is $696 more than what they need to pay. This amount is x+ 696

Mathematically, this can be represented as;

7x/8 + 35x/48 = x + 696

(42x + 35x)/48 = (x + 696)

77x/48 = (x + 696)

77x = 48(x + 696)

77x = 48x + 33408

77x - 48x = 33408

29x = 33, 408

x = 33,408/29

x = $1,152

7 0

3 years ago