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VMariaS [17]
3 years ago
14

How many shapes are in the world

Mathematics
2 answers:
bagirrra123 [75]3 years ago
7 0
There are more than you think ;) There is no limit to shapes, everything comes in shapes and sizes. For example,  A computer has soft edges and it is rectangular. Peole can make up shapes if they want to, But more the merrier!
Montano1993 [528]3 years ago
3 0
There are an infinite number of shapes, because a shape can have any number of sides. This is where we get into our laws of fractals. A fractal is a shape with an infinite perimeter and area, meaning that every level of infinity is another shape, but can be beat by another shape. However, this is all philosophical math and goes way beyond the context of your question.

To keep it short and simple, there are an infinite number of shapes in the world.
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8 0
3 years ago
Read 2 more answers
Someone please help me with this!!
Paraphin [41]

PEMDAS tells us to use multiplication and division before addition and subtraction.

<u>-5(8) </u>÷ 10 - <u>14 ÷ 7</u> - <u>(-2)(3)</u>

<u> -40  ÷ 10</u> -     2    -   -6

     <u>-4       -    2 </u>     + 6    <em>two negatives make a positive so - - 6  = + 6</em>

           <u> -6              +6</u>

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Answer: 0


3 0
3 years ago
Whats the value of T in -1+14+-3t+10
Ira Lisetskai [31]

Answer:

how can I find the value of t when it is not equated

Step-by-step explanation:

still on that

6 0
3 years ago
PLEASE HELP!!!
Salsk061 [2.6K]
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4 0
3 years ago
Solve by elimination.<br> 5x-7y=19<br> 7x-7y=-7
SVEN [57.7K]

Answer:

(x,y)=(-13,-12)

Step-by-step explanation:

5x - 7y = 19

7x - 7y = -7  Multiply both sides of the equation by -1

Which then gives you :

5x-7y=19  Sum the equations vertically to eliminate  

-7x+7y=7                 at least on variable

-2x=26      Divide both sides of the equation by -2

X=-13       Substitute the given value of x into the equation 7x - 7y =-7

7 x(-13)-7y=-7 solve the equation for y

y=-12

Thus gives you (-13,-12)

Hope this was useful!!! Sorry if it's wrong.

4 0
3 years ago
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