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Ilia_Sergeevich [38]
3 years ago
5

Multiply

Mathematics
1 answer:
algol [13]3 years ago
5 0

When a matrix is multiplied by a constant, the constant multiplies each of the elements of the matrix.

2\left[\begin{array}{cc}4&0\\-1&5\end{array}\right]=\left[\begin{array}{cc}2\cdot 4&2\cdot 0\\2\cdot(-1)&2\cdot 5\end{array}\right]\\\\=\left[\begin{array}{cc}8&0\\-2&10\end{array}\right]

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Mr eliot is extremely careful with his money. He recently invested part of his $150,000 life savings in gold bullion and the res
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Answer:

The amount invested in gold bullion by Mr. Eliot  =   $50,000

Step-by-step explanation:

Total amount of savings Me. Eliot ha s = $150,000

Let us assume the amount invested in gold bullion = $m

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Now, 5% on m = \frac{5}{100}  \times m = 0.05 m

So, the profit in gold bullion  =  0.05 m

and 3% on (150,000 -m)   = \frac{3}{100}  \times  (150,000 -m) = 0.03  (150,000 -m)

= 4,500 - 0.03 m

So, the profit in bank =  4,500 - 0.03 m

Now,  the total profit  = $5,500

⇒Profit from gold bullion + ban = $5,500

⇒0.05 m +  4,500 - 0.03 m = $5,500

or, 0.02 m = 1000

⇒ m = 1000/0.02 = 50,000

Hence, the amount invested in gold bullion  =  m = $50,000

3 0
3 years ago
Theresa Mitsoto invested $3,500 in a 3-year CD that paid 6.5% annual interest. She cashed out the CD at the end of two years wit
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Answer:

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Step-by-step explanation:

Given that :

Amount invested = principal, p = 3500

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Time = 3 months = 3/12 = 0.25 years

Hence,

Simple interest = 3500 * 0.065 * 0.25

Simple interest = $56.875

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Answer:

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7 0
1 year ago
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