Answer:
a) After adding the 0 test score, the mean would be the most appropriate measure of center to describe the data-------> is true
b) After adding the 0 test score, the mean would be affected-----> is true
c) After adding the 0 test score, the median would be the most appropriate measure of center to describe the data-----> is false
d) Before the missed test, Eva’s median score was 96-----> is false
e) Before the missed test, Eva’s median score was 91------ is true
f) Before the missed test, Eva’s mean score was 91.8-----> is true
Step-by-step explanation:
Hope this helps:)
Answer:
20kg of $0.89 candy
10kg of $1.10 candy
Step-by-step explanation:
Candy 1 = 0.89 per kg
Candy 2 = 1.10 per kg
Total kilogram, kg = 30
Let candy 1 = x ; candy 2 = (30 - x) ;
0.89x + 1.10(30 - x) = 0.96(30)
0.89x + 33 - 1.10x = 28.8
0.89x - 1.10x = 28.8 - 33
-0.21x = - 4.2
x = 4.2 / 0.21
x = 20
20kg of $0.89 candy
(30 - x) = (30 - 20) = 10kg
10kg of $1.10 candy
Answer:Determine" (and any subsequent words) was ignored because we limit queries to 32 words.
The answer is a=35,000 and equation is a=t-g/-0.0035
Step-by-step explanation:
Answer:
8.69565217391 m per sec
8.7 (1dp)
Step-by-step explanation:
