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3 years ago

Write an equation of a line thru (3,-1) and (-1,-7)

2 answers:

8 0

Slope form M=y2-y1/x2-x2 M= -7 -(-1)/-1-3 M= -6/-4 M=3/2 So 3/2 is your slope Now use one if the pair points (3,-1) and slope to find b. -1=2/3(3)+b -1=2+b -1-2=b -3=b Y=2/3x-3

Marrrta [24]3 years ago

6 0

-1 - (-7) over 3 - (-1) = M

-1 + 7 over 3 + 1 = M

6 over 4 = M

6/4 = M

3/2 = M

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What is 0.3636... round to the nearest tenth?

miskamm [114]

0.36.
tenth position is b in . 0.ab

6 0

3 years ago

Which of the following matrices is the solution matrix for the given system of equations? x + 5y = 11 x - y = 5

givi [52]

<h2>The required solution is x = 6 and y = 11 </h2>

Step-by-step explanation:

Given system of equations are

x+5y = 11 and x-y =5

$A= \left[\begin{array}{cc}1&5\\1&-1\end{array}\right]$ $X=\left[\begin{array}{c}x\\y\end{array}\right]$

and $B= \left[\begin{array}{c}11\\5\end{array}\right]$

∴AX=B

$adj A = \left[\begin{array}{cc}{-1}&{-5}\\{-1}&1\end{array}\right]$

$A= \left|\begin{array}{cc}1&5\\1&-1\end{array}\right|=-6$

∴ $A^{-1} =\frac{adj A}{|A|}$

So, $A^{-1} =\frac{ \left[\begin{array}{cc}{-1}&{-5}\\{-1}&1\end{array}\right]}{-6}$

$A^{-1} ={ \left[\begin{array}{c \c} {{\frac{1}{6} }}&{\frac{5}{6}}\ \\ {{\frac{1}{6} }}&{\frac{-1}{6}} \end{array}\right]}$

$X =A^{-1}\times B$

⇒ $\left[\begin{array}{c}x\\y\end{array}\right] ={ \left[\begin{array}{c \c} {{\frac{1}{6} }}&{\frac{5}{6}}\ \\ {{\frac{1}{6} }}&{\frac{-1}{6}} \end{array}\right]} \times \left[\begin{array}{c}11\\5\end{array}\right]$

⇒ $\left[\begin{array}{c}x\\y\end{array}\right] ={ \left[\begin{array}{c} {6}\\ {11} \end{array}\right]}$

∴ x= 6 and y = 11

The required solution is x = 6 and y = 11

7 0

2 years ago

In the figure below, ⎯⎯⎯⎯⎯⎯⎯⎯,⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯, and ⎯⎯⎯⎯⎯⎯⎯⎯⎯ are medians of △. If KC = 108 and OC = 2n+10, then n=

Nimfa-mama [501]

The question was incomplete. Below you will find the missing content.

In the figure below, BL, AM, and CK are medians of △ABC. If KC = 108 and OC = 2n + 10, then n=

The picture is attached below.

The value of n is 31.

The median is the line connecting the vertex and its midpoint on the opposite side of the triangle.

The intersection of all 3 medians of the triangle is called the centroid.

As we know centroid divides the median in the ratio of 2:1.

In the given picture,

Medians of triangle △ABC are AM, BL, and CK.

So the centroid of the triangle is O.

Given that KC= 108

As the centroid O divides the line KC in 2:1.

Let OC=2x

KO= X

As KC= KO+OC

⇒ 108= x+2x

⇒ 3x=108

⇒ x=108/3

⇒ x=36

Then OC= 2x= 2*36= 72

As given in the question OC= 2n+10

putting the value of OC in above equation

⇒ 72= 2n+10

⇒ 2n= 72-10

⇒ 2n=62

⇒ n=62/2

⇒n=31

Therefore the value of n is 31.

Learn more about the median of the triangle

here: brainly.com/question/2264495

#SPJ10

5 0

2 years ago

One-half of a number,<br> increased by 69 is 74.<br> What is the number?

Klio2033 [76]

Answer:

Step-by-step explanation:

let the number be n then half the number is $\frac{1}{2}$ n , so

$\frac{1}{2}$ n + 69 = 74 ( subtract 69 from both sides )

$\frac{1}{2}$ n = 5 ( multiply both sides by 2 to clear the fraction )

n = 10

Thus the number is 10

6 0

2 years ago

Read 2 more answers

Parallel to y=−3/4x, through (4, -1)

kolbaska11 [484]

Answer:

$y=-\frac{3}{4}x+2$

Step-by-step explanation:

The slope-intercept form is given by y=mx+c, where m is the slope and c is the y-intercept.

Slope of given line= $-\frac{3}{4}$

Parallel lines have the same slope. Thus, the slope of the line would also be $-\frac{3}{4}$ .

$y=-\frac{3}{4}x +c$

The value of c can be found by substituting a pair of coordinates.

When x= 4, y= -1,

$-1=-\frac{3}{4} (4)+c$

-1= -3 +c

<em>Add 3 to both sides:</em>

c= -1 +3

c= 2

Thus, the equation of the line is $\bf{y=-\frac{3}{4}x+2$ .

Additional:

Do check out the following for a similar question on slope-intercept form!

brainly.com/question/25549430

7 0

2 years ago