Answer:
h = 61.25 m
Step-by-step explanation:
It is given that,
The initial velocity of the ball, v = 60 m/s
It is thrown from a height of 5 feet, 
We need to find the maximum height it reaches. The height reached by the projectile as a function of time t is given by :
Putting all the values,
.....(1)
For maximum height, put
Put t = 1.875 in equation (1)
So, the maximum height reached by the ball is 61.25 m.
The correct answer is A) g≥5
This is because when you look at an absolute value function, the constant at the end is the y value of the vertex. Since it is an absolute value equation, we know that the values can only go up. Therefore, it must be greater than or equal to the constant at the end (5)
Answer:
60.59
Step-by-step explanation:
73%=0.73
0.73*83=60.59
-14+3/2b-(1+2/8b), then take out the blanket become -14+3/2b-1-2/8b , get 5/4b-15=0 so 5/4b=15 ,get b=15×4÷5. b=12
Answer: Option D. 1,778
Solution:
Standard brick:
Width: w=3.625 in
Height: h=2.25 in
Length: l=7.625 in
Volumen of one standard brick: v
v=w*h*l
v=(3.625 in)*(2.25 in)*(7.625 in)
v=62.19140625 in^3
Pallet of bricks:
Side: s=4 feet
s=(4 feet)*(12 in / 1 feet)→s=48 in
Volume of a pallet of bricks: V=s^3
V=(48 in)^3
V=110,592 in^3
Number of bricks could be in a pallet: n
n=V/v
n=(110,592 in^3) / (62.19140625 in^3)
n=1,778.252119
n=1,778
