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Colt1911 [192]
3 years ago
7

A clothing company sells slacks that are either blue or gray and pleated or non-pleated. Last month, the company sold 5 times as

many pairs of blue pleated slacks as gray pleated slacks, and it sold twice as many pairs of gray non-pleated slacks as blue non-pleated slacks. If it sold 333 pairs of blue slacks and 225 pairs of gray slacks, how many pairs of blue non-pleated slacks did it sell?
Mathematics
1 answer:
qwelly [4]3 years ago
3 0

Answer:

138 pairs

Step-by-step explanation:

The number of blue pleated slacks is 5 times the number of gray pleated slacks, so:

blue\ pleated = 5 * gray\ pleated (eq1)

The number of gray non-pleated is twice the number of blue non-pleated slacks, so:

blue\ nonpleated = 2 * gray\ nonpleated (eq2)

The total number of blue slacks is 333, and the total number of gray slacks is 225, so we have that:

blue\ pleated + blue\ nonpleated = 333 (eq3)

gray\ pleated + gray\ nonpleated = 225 (eq4)

If we add (eq1) and (eq2), we have:

blue\ pleated + blue\ nonpleated = 5*gray\ pleated + 2*gray\ nonpleated (eq5)

Using (eq3) and (eq4) in (eq5), we have:

333 = 2*225 + 3*gray\ pleated

gray\ pleated = 117/3 = 39

From (eq1), we have:

blue\ pleated = 5*39 = 195

From (eq3), we have:

blue\ nonpleated = 333 - 195 = 138

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Answer:

a.  X~N(2,885, 651)

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Step-by-step explanation:

a. -A normal distribution is expressed in the form X~N(mean, standard deviation).

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-X is a is a normally distributed random variable with mean 2885 and standard deviation 651.

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b. The probability that less than 2000 calories are consumed is calculated using the formula:

P(X

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P(X

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c. The proportion of customers consuming more than 5000 calories is calculated as:

P(X>x)=P(z>\frac{\bar X-\mu}{\sigma})\\\\=P(Z>\frac{5000-2885}{651})\\\\=P(z>3.2488)\\\\=1-0.99942\\\\=0.00058

Hence, the proportion of customers consuming over  5000 calories is 0.00058

d. The least amount of calories to get the award is calculated as:

1% is equivalent to a z value of 0.50399.

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0.01=P(z>\frac{\bar X-\mu}{\sigma})\\\\=P(z>\frac{\bar X-2885}{651})\\\\\1\%=0.50399 \\\\\frac{\bar X-2885}{651}=0.50399 \\\\\bar X=0.50399\times 651+2885\\\\=3213.09

Hence, the least amount of calories consumed to qualify for the award is 3213.10 calories.

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abruzzese [7]

Answer:

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