$\dfrac{1-\cos135^\circ}{\sin135^\circ}=\dfrac{1-\left(\cos^2 67.5^\circ-\sin^2 67.5^\circ\right)}{2\sin67.5^\circ\cos67.5^\circ}=\dfrac{1-\left(1-\sin^2 67.5^\circ-\sin^2 67.5^\circ\right)}{2\sin67.5^\circ\cos67.5^\circ}=\medskip\\=\dfrac{2\sin^2 67.5^\circ}{2\sin67.5^\circ\cos67.5^\circ}=\dfrac{\sin 67.5^\circ}{\cos 67.5^\circ}=\tan 67.5^\circ$

3 0

3 years ago

Find the perimeter and simplify your answer

Lera25 [3.4K]

Answer:

32z-14

Step-by-step explanation:

2(9z-8)+2(7z+1)

18z-16+14z+2

simplify

32z-14

3 0

3 years ago

Which of the following equations has the same solutions as the equation 3x + 2y= -12

tatuchka [14]

Answer:

x= -2/3y-4

Step-by-step explanation:

3x+2y=-12

3x+2y-2y= -2y-12

3x=-2y-12

3x/3= -2y/3-12/3

x= -2/3y-4

6 0

3 years ago