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Yuri [45]
3 years ago
8

Verdadero o Falso:

Mathematics
1 answer:
crimeas [40]3 years ago
8 0
B is the correct answer
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Solve for q. √3q + 2 = √5
34kurt

Answer:

q = 0.0186

Step-by-step explanation:

To solve for q, we initially place everything with the term q to one side of the equality, and everything without the term q to the other side of the equality.

So

\sqrt{3q} + 2 = \sqrt{5}

\sqrt{3q} = \sqrt{5} - 2

We find the square of both sides of the equation. So

(\sqrt{3q})^{2} = (\sqrt{5} - 2)^{2}

3q = 0.0557

q = \frac{0.0557}{3}

q = 0.0186

8 0
4 years ago
(-9,5); m=4 right and equation in point slope form of the line that passes through the given point and with the given slope M
NikAS [45]

Answer:

Slope form of line  y = 4x +41

Step-by-step explanation:

m= 4

The y-intercept of the line that passes through the given point  (-9,5) is

5 = 4(-9) + b

b= 5 +36

b=41

The equation of the line that passes through the given point  (-9,5) is

y =mx +b

 y = 4x +41

6 0
2 years ago
A research team conducted a study showing that approximately 20% of all businessmen who wear ties wear them so tightly that they
ch4aika [34]

The probabilities that the at least one tie is too tight is 0.878 and more than two ties are too tight is 0.323 and none are too tight is 0.122 and at least 18 are NOT too tight is 0.67.

According to the statement

We have given that the in a survey showing that the approximately 20% of all businessmen who wear ties wear them so tightly that they actually reduce blood flow to the brain.

And we have to find the probability on the some given conditions.

So, For this purpose, we know that the

The probability is the measure of the likelihood of an event to happen. It measures the certainty of the event.

Now,

A. Here n = 20, P = 0.1, And  X ≥ 1. Then

The probability that at least one tie is too tight P(≥ 1) = 1 - P(0)

P(≥ 1) = 1 - 0.12

P(≥ 1) = 0.878.

And

B. Here P(≤2) = 0.67 Then

The probability that more than two ties are too tight P(≥ 3) = 1 - P(≤2)

P(≥ 3) = 1 - 0.67

P(≥ 3) = 0.323

And

C. The probability that none are too tight P(0) = 0.122.

And

D. Here n =20, P = 0.1 and X≤2

The probability that at least 18 are NOT too tight P(X≤2) = 0.67.

So, The probabilities that the at least one tie is too tight is 0.878 and more than two ties are too tight is 0.323 and none are too tight is 0.122 and at least 18 are NOT too tight is 0.67.

Learn more about probabilities  here

brainly.com/question/24756209

Disclaimer: This question was incomplete. Please find the full content below.

Question:

A research team conducted a study showing that approximately 20% of all businessmen who wear ties wear them so tightly that they actually reduce blood flow to the brain, diminishing cerebral functions. At a board meeting of 15 businessmen, all of whom wear ties, what are the following probabilities

A. What is the probability that at least one tie is too tight?

B. What is the probability that more than two ties are too tight?

C. What is the probability that none are too tight?

D. What is the probability that at least 18 are NOT too tight?

#SPJ4

4 0
2 years ago
Solve x^2+11X<-8 Urgent please help!!!!!
Tamiku [17]
Add 121/4 to each side:
x²+11x+121/4 < 121/4-8
x²+11x+121/4 < 89/4
(x+11/2)² < √89/2 ⇒ -√89/2 < x+11/2 < √89/2
-11/2-√89/2 < x < -11/2+√89/2
8 0
3 years ago
Use the given values of n and p to find the minimum usual value μ - 2σ and the maximum usual value μ + 2σ. Round your answer to
fenix001 [56]

Given Information:  

number of trials = n = 1042

Probability of success = p = 0.80

Required Information:  

Maximum usual value = μ + 2σ = ?

Minimum usual value = μ - 2σ = ?

Answer:

Maximum usual value = 859.51

Minimum usual value = 807.78

Step-by-step explanation:

In a binomial distribution, the mean μ is given by

μ = np

μ = 1042*0.80

μ = 833.6

The standard deviation is given by

σ = √np(1 - p)

σ = √1042*0.80(1 - 0.80)

σ = √833.6(0.20)

σ = 12.91

The Maximum and Minimum usual values are

μ + 2σ = 833.6 + 2*12.91

μ + 2σ = 833.6 + 25.82

μ + 2σ = 859.51

μ - 2σ = 833.6 - 25.82

μ - 2σ = 807.78

Therefore, the minimum usual value is 807.78 and maximum usual value is 859.51

8 0
4 years ago
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