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4 years ago

Again.. your girl needs help again ..

Mathematics

1 answer:

Maru [420]4 years ago

6 0

<u>Answer:</u> C. $3x^{2}$ + $3$

<u>Explanation:</u> you basically combine f(x) and g(x).

$2x^{2} + 5 + x^{2} -2$ combine your terms

$3x^{2} + 2$ your final answer

hope this helps!❤ from peachimin

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Someone help me please !!!

LenaWriter [7]

Yes it is a function

3 0

3 years ago

Radha and her 5 friends took part in a marathon relay. they ran a total distance of 42 km and 195 m. if each friend ran 7 km, ho

Mariulka [41]

Let the total distance travelled by Radha be x .

Total number of friend = 5

total distance travelled by each friend is 7 km

$\\$

so,

$\\$

$\large{\mapsto{x\:+\:7\:×\:5\:=\:42.195}}$

$\large{\mapsto{x\:+\:35\:=\:42.195}}$

$\large{\mapsto{x\:=\:42.195\:-\:35}}$

$\large{\mapsto{x\:=\:7.195\:km}}$

as per our assumption .

that total distance travelled by Radha is x

so total distance travelled by Radha is 7.195 km

5 0

3 years ago

Read 2 more answers

What is Quadrilateral!?

deff fn [24]

Answer:

Hi, There! I'll be Happy to help you (っ◕‿◕)っ ♥

<h2>Question</h2>

What is Quadrilateral!?

<h2>Answer</h2>

a quadrilateral can be defined as a closed, two-dimensional shape that has four straight sides. ✔

Step-by-step explanation:

<h3>Here are examples of Quadrilaterals</h3>

The seven types of quadrilaterals are parallelogram, rhombus, kite, rectangle, trapezoid, square, and isosceles trapezoid. ✔

<h3>Properties</h3>

<em>The sides do not have to be the same length. Quadrilaterals have four sides, four vertices, and four interior angles that add up to 360</em>°✔

Therefore, I hope this helps! ツ

8 0

3 years ago

We are standing on the top of a 1680 ft tall building and throw a small object upwards. At every second, we measure the distance

MAVERICK [17]

Answer:

a) The height of the small object 3 seconds after being launched is 2304 feet.

b) The small object ascends 128 feet between 5 seconds and 7 seconds.

c) The object will take 6 and 10 seconds after launch to reach a height of 2640 feet.

d) The object will take 21 seconds to hit the ground.

Step-by-step explanation:

The correct formula for the height of the small object is:

$h(t) = -16\cdot t^{2}+256\cdot t+1680$ (1)

Where:

$h$ - Height above the ground, measured in feet.

$t$ - Time, measured in seconds.

a) The height of the small object at given time is found by evaluating the function:

$h(3\,s)= -16\cdot (3\,s)^{2}+256\cdot (3\,s)+1680$

$h(3\,s) = 2304\,ft$

The height of the small object 3 seconds after being launched is 2304 feet.

b) First, we evaluate the function at $t = 5\,s$ and $t = 7\,s$ :

$h(5\,s)= -16\cdot (5\,s)^{2}+256\cdot (5\,s)+1680$

$h(5\,s) = 2560\,s$

$h(7\,s)= -16\cdot (7\,s)^{2}+256\cdot (7\,s)+1680$

$h(7\,s) = 2688\,s$

We notice that the small object ascends in the given interval.

$\Delta h = h(7\,s)-h(5\,s)$

$\Delta h = 128\,ft$

The small object ascends 128 feet between 5 seconds and 7 seconds.

c) If we know that $h = 2640\,ft$ , then (1) is reduced into this second-order polynomial:

$-16\cdot t^{2}+256\cdot t-960=0$ (2)

All roots of the resulting equation come from the Quadratic Formula:

$t_{1} = 10\,s$ and $t_{2}= 6\,s$

The object will take 6 and 10 seconds after launch to reach a height of 2640 feet.

d) If we know that $h = 0\,ft$ , then (1) is reduced into this second-order polynomial:

$-16\cdot t^{2}+256\cdot t +1680 = 0$ (3)

All roots of the resulting equation come from the Quadratic Formula:

$t_{1} = 21\,s$ and $t_{2} = -5\,s$

Just the first root offers a solution that is physically reasonable.

The object will take 21 seconds to hit the ground.

8 0

3 years ago

An ice cream cone is made of a cone shape and half a sphere shape. Explain how you could find the volume of the entire ice cream

kondor19780726 [428]

Call the radius r and the height of the cone h. The formula for the volume of a cone is r^2*h*pi/3, and the formula for the volume of a sphere is 4r^3/3, so half of a sphere has volume 2r^3/3. Adding these, our answer is:

$\frac{r^2 h \pi+r^3}{3}$

4 0

3 years ago