Answer:
0.0623 ± ( 2.056 )( 0.0224 ) can be used to compute a 95% confidence interval for the slope of the population regression line of y on x
Step-by-step explanation:
Given the data in the question;
sample size n = 28
slope of the least squares regression line of y on x or sample estimate = 0.0623
standard error = 0.0224
95% confidence interval
level of significance ∝ = 1 - 95% = 1 - 0.95 = 0.05
degree of freedom df = n - 2 = 28 - 2 = 26
∴ the equation will be;
⇒ sample estimate ± ( t-test) ( standard error )
⇒ sample estimate ± (
) ( standard error )
⇒ sample estimate ± (
) ( standard error )
⇒ sample estimate ± (
) ( standard error )
{ from t table; (
) = 2.055529 = 2.056
so we substitute
⇒ 0.0623 ± ( 2.056 )( 0.0224 )
Therefore, 0.0623 ± ( 2.056 )( 0.0224 ) can be used to compute a 95% confidence interval for the slope of the population regression line of y on x
Answer:
-6.5 would be your answer
Step-by-step explanation:
Answer:
{0,6}
Step-by-step explanation:
-2x^2+12x = 0
Factor out a -2x
-2x(x-6) =0
Using the zero product property
-2x = 0 and x-6=0
-2x = 0
Divide by -2
-2x/-2 = 0/-2
x=0
x-6=0
Add 6 to each side
x-6+6 =0+6
x=6
The solutions are 0 and 6
Use the slope formula
y2-y1
m=---------
x2-x1
(rise-->y over run-->x)
so it would be
9-5
m=-------
1-10
and that would simplify to
4
----
-9
and that would be your slope.
Hope that helped :-)