Question

A 22 ft ladder is set up 6 feet from the base of the building. How far up the building does the ladder reach. Round to the nearest tenth of a foot

Answer 1

Answer:

Let AB be the height of the building and B be the base as shown in the figure.

Using Pythagoras Theorem,

$AC^{2} =AB^{2} +BC^{2} \\or, 22^{2}= AB^{2}+ 6^{2} \\or, 484 = AB^{2} +36\\or, AB^{2} = 448\\or, AB = 8\sqrt{7} feet\\So, the ladder reaches 8\sqrt{7} feet far from the building$

Answer 2

Answer

13.2

Step-by-step explanation:

bcuz i did it on egde 2021