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4 years ago

What is 489,493-763=?

Mathematics

1 answer:

Free_Kalibri [48]4 years ago

8 0

Answer:

488,730

Step-by-step explanation:

Imagine you had 489,493 (anything) and you take away 763.

It would give you 488,730!

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Find the domain of the function.<br> f(x) = x² - 9x - 15<br> What is the domain off?

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The domain of the function is all real numbers because it is a quadratic equation

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3 years ago

Pls help being timed

Vlad1618 [11]

The answer you need is -2

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Jane must get at least three of the four problems on the exam correct to get an A. She has been able to do 80% of the problems o

NISA [10]

Answer:

a) There is n 81.92% probability that she gets an A.

b) If she gets the first problem correct, there is an 89.6% probability that she gets an A.

Step-by-step explanation:

For each question, there are only two possible outcomes. Either the answer is correct, or it is not. This means that we can solve this problem using binomial distribution probability concepts.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

For this problem, we have that:

The probability she gets any problem correct is 0.8, so $\pi = 0.8$ .

(a) What is the probability she gets an A?

There are four problems, so $n = 4$

Jane must get at least three of the four problems on the exam correct to get an A.

So, we need to find $P(X \geq 3)$

$P(X \geq 3) = P(X = 3) + P(X = 4)$

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 3) = C_{4,3}.(0.80)^{3}.(0.2)^{1} = 0.4096$

$P(X = 4) = C_{4,4}.(0.80)^{4}.(0.2)^{0} = 0.4096$

$P(X \geq 3) = P(X = 3) + P(X = 4) = 2*0.4096 = 0.8192$

There is n 81.92% probability that she gets an A.

(b) If she gets the first problem correct, what is the probability she gets an A?

Now, there are only 3 problems left, so $n = 3$

To get an A, she must get at least 2 of them right, since one(the first one) she has already got it correct.

So, we need to find $P(X \geq 2)$

$P(X \geq 3) = P(X = 2) + P(X = 3)$

$P(X = 2) = C_{3,2}.(0.80)^{2}.(0.2)^{1} = 0.384$

$P(X = 4) = C_{3,3}.(0.80)^{3}.(0.2)^{0} = 0.512$

$P(X \geq 3) = P(X = 2) + P(X = 3) = 0.384 + 0.512 = 0.896$

If she gets the first problem correct, there is an 89.6% probability that she gets an A.

3 0

4 years ago

At the local market, Bill buys 3 juice boxes and 2 hot dogs at a cost of $8, while Sarah buys 2 juice boxes and 1 hot dog at a c

baherus [9]

Answer:

The cost of each juice boxes is $ 2

The cost of each hot dogs is $ 1 .

Step-by-step explanation:

Given as :

The amount which Bill pays for 3 juice boxes and 2 hot dogs = $ 8

The amount which Sarah pays for 2 juice boxes and 1 hot dogs = $ 5

Let The cost of each juice boxes = $ j

And The cost of each hot dogs = $ h

Now, According to question

3 j + 2 h = 8 .........A

2 j + 1 h = 5 ..........B

Now, solving the equations

2 × ( 2 j + 1 h ) = 2 × 5

or, 4 j + 2 h = 10

I.e ( 4 j + 2 h ) - ( 3 j + 2 h ) = 10 - 8

Or, ( 4 j - 3 j ) + ( 2 j - 2 h ) = 2

Or, j + 0 = 2

∴ j = 2

So , The cost of each juice boxes = j = $ 2

Now, Put the value of j in Eq A

I.e 3 × 2 + 2 h = 8

Or, 6 + 2 h = 8

Or. 2 h = 8 - 6

or, 2 h = 2

∴ h = $\frac{2}{2}$ = 1

So, The cost of each hot dogs = h = $ 1

Hence The cost of each juice boxes is $ 2

And The cost of each hot dogs is $ 1 . Answer

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4 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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