Answer:
Step-by-step explanation:
Here's how you convert:
The little number outside the radical, called the index, serves as the denominator in the rational power, and the power on the x inside the radical serves as the numerator in the rational power on the x.
A couple of examples:
![\sqrt[3]{x^4}=x^{\frac{4}{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E4%7D%3Dx%5E%7B%5Cfrac%7B4%7D%7B3%7D)
![\sqrt[5]{x^7}=x^{\frac{7}{5}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Bx%5E7%7D%3Dx%5E%7B%5Cfrac%7B7%7D%7B5%7D)
It's that simple. For your problem in particular:
is the exact same thing as ![\sqrt[3]{7^1}=7^{\frac{1}{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B7%5E1%7D%3D7%5E%7B%5Cfrac%7B1%7D%7B3%7D)
Answer:
it would 13
Step-by-step explanation:
19-6=13 there you go
<h3>
Answer: 8</h3>
=======================================================
Work Shown:
Let's say there are 28 cards in a full stack.
6/7 = 24/28 after multiplying top and bottom by 4
Since he has 24/28 of a stack left, this means he has 24 cards left.
He wants to arrange the remaining cards into piles so that each pile consists of 3/28 of a full stack. In other words, he wants each pile to have 3 cards.
So this must mean he will get 24/3 = 8 piles
(8 piles)*(3 cards per pile) = 8*3 = 24 cards total
Answer:
Step-by-step explanation:
5x+14<4 or -2(x-8)<-2
-14 -14 -2x+16<-2
5x<-10 -16 -16
÷5 ÷5 -2x<-18
x<-2 ÷-2 ÷-2
x>9 (sign changes because you divide by a negative number)
x<-2 or x>9