Answer:
its c if I'm not wrong.......
Hello!
First we look at the equation to find two points and the y intercept
The y-intercept is (0, -6)
The slope is 4 so two of the points are (1, -2) and (2, 2)
Now we look at the inequality sign
Since the sign is less than the line is going to be a dotted line and the section underneath the line is going to be shaded in
The graph should have a dotted line that goes through the points (0, 6),
(1, -2) and (2, 2) with the section to the right of the line shaded in
Hope this helps!
Answer:
4 and 6
Step-by-step explanation:
First, let's find all the pairs that add up to 10.
- 1 + 9, 2 + 8, 3 + 7, 4 + 6, and 5 + 5
Next, we find the difference between the addends for each pair.
- 9 - 1 = 8
- 8 - 2 = 6
- 7 - 3 = 4
- 6 - 4 = 2
- 5 - 5 = 0
As you can, see the numbers that add to 10 and have a different of 2 is 4 and 6.
Given:
The points are (-3, 2) and (2, -13).
To find:
Slope-intercept form of the equation.
Solution:
Here
.
Slope of the line:
![$m=\frac{y_2-y_1}{x_2-x_1}](https://tex.z-dn.net/?f=%24m%3D%5Cfrac%7By_2-y_1%7D%7Bx_2-x_1%7D)
![$m=\frac{-13-2}{2-(-3)}](https://tex.z-dn.net/?f=%24m%3D%5Cfrac%7B-13-2%7D%7B2-%28-3%29%7D)
![$m=\frac{-15}{5}](https://tex.z-dn.net/?f=%24m%3D%5Cfrac%7B-15%7D%7B5%7D)
m = -3
Using point-slope formula:
![y-y_1=m(x-x_1)](https://tex.z-dn.net/?f=y-y_1%3Dm%28x-x_1%29)
![y-2=-3(x-(-3))](https://tex.z-dn.net/?f=y-2%3D-3%28x-%28-3%29%29)
![y-2=-3(x+3)](https://tex.z-dn.net/?f=y-2%3D-3%28x%2B3%29)
![y-2=-3x-9](https://tex.z-dn.net/?f=y-2%3D-3x-9)
Add 2 on both sides.
![y-2+2=-3x-9+2](https://tex.z-dn.net/?f=y-2%2B2%3D-3x-9%2B2)
![y=-3x-7](https://tex.z-dn.net/?f=y%3D-3x-7)
Slope-intercept form of the equation is y = -3x - 7.