Answer:
It will take her 13 hours
Answer:
$21.50
Step-by-step explanation:
Mr. Gutierrez had $100 to purchase candy for his students that completed their work.
He bought 8 bags of jolly ranchers
Each bag of jolly ranchers cost $3.25.
Hence, the cost of 8 bags of jolly ranchers = 8 × $3.25
= $26
He also bought 25 bags of assorted chocolate and each bag of assorted chocolate cost $2.10.
Hence, the cost of 25 bags of assorted chocolates = 25 × $2.10
= $52.5
Therefore, the amount of money Mr. Gutierrez has left over after these purchases is calculated as:
Total amount - Sum of ( Cost of 8 bags of jolly ranchers + 25 bags of assorted chocolates)
= $100 - ( $26 + $52.5)
= $100 - $78.50
= $21.50
Answer: The numbers whose sum equals 12 and whose product and difference is largest is 6 and 6
Step-by-step explanation:
numbers whose sum is 12
Sum =12 Product Difference Product- Difference
11 +1 11 10 1
10 +2 20 8 12
9 +3 27 6 21
8 +4 32 4 28
7 +5 35 2 33
6+6 36 0 36
The numbers whose sum equals 12 and whose product and difference is largest is 6 and 6
Answer:
a. 0.12109
b. 0.0001668
c .0.9726
d. 0.01038
e. 0.01211
f. 0.000001731
Step-by-step explanation:
Sample size = 580
Defective units = 8
Number of picks = 2
a) If the first container is defective, there 7 defective containers left in a population of 579. The probability of selecting a defective one is:

b) The probability that both are defective is given by:

c) The probability that both are acceptable is given by:

d) In this case, two defective units were removed from the batch, the probability that the third is also defective is:

e) In this case, one acceptable and one defective unit were removed from the batch, the probability that the third is also defective is:

f) The probability that all three are defective is given by:

Answer: 76.2
Step-by-step explanation:
Perimetar of isiscales triangle is calculated using equation;
P=b+2a
b=9
P=49
lets find sides of triangle.
P-b=2a
a=(P-b)/2
a=49-9/2
a=40/2=20
If another triangle is similar that means that his base and sides are proportional to first triangle.
Base of first trianlge b₁=9
Base of similar triangle is b₂=14
use proportion to find out side of similar triangle:
b₁:b₂=9:14
a₁:a₂=9:14
a₁=20
20: a₂=9:14
a₂=14*20/9=280/9=31.1
Perimetar of second triangle is:
P₂=b₂+2a₂
P₂=14+2*31.1=14+62.2=76.2