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Advocard [28]
3 years ago
14

Make x the subject of these equations. Thanks ^^

Mathematics
2 answers:
deff fn [24]3 years ago
4 0

Answer:

x=w-v/13

x=b-4/(a-3)

x=y+w/(5-v)

x=6/(v+w)

x=13v/(5w-8)

Step-by-step explanation:

We are to make x the subject of formula

So let's solve

9x+v=4x+w

Let's collect like terms

9x-4x=w-v

13x=w-v

Divide both sides by 13

x=w-v/13

ax+4=3x+b

Collect like terms

ax-3x=b-4

x(a-3)=b-4

x=b-4/(a-3)

5x-w=vx+y

Collect like terms

5x-vx=y+w

x(5-v)=y+w

x=y+w/(5-v)

7-wx=vx+1

Collect like terms

7-1=vx+wx

6=x(v+w)

x=6/(v+w)

5(wx-v)=8(x+v)

Open the bracket

5wx-5v=8x+8v

Collect like terms

5wx-8x=8v+5v

x(5w-8)=13v

x=13v/(5w-8)

damaskus [11]3 years ago
3 0

9x + v = 4x + w \\ 9x - 4x = w - v \\ 5x = w - v \\ x =  \frac{w - v}{5}

ax + 4 = 3x + b \\ ax - 3x = b - 4 \\ x(a - 3) = b - 4 \\  \frac{x(a - 3)}{(a - 3)}  =  \frac{b - 4}{(a - 3)}  \\ x =  \frac{b - 4}{(a - 3)}

7  - wx = vx + 1 \\  - wx - vx = 1 - 7 \\  - x(w + v) =  - 6 \\ x =  \frac{6}{(w + v)}

5(wx - v) = 8(x + v) \\ 5wx - 5v = 8x + 8v \\ 5wx - 8x = 5v + 8v  \\ x(5w - 8) = 13v \\ x =  \frac{13v}{(5w - 8)}

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4 0
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I need help with the bottom question
Sati [7]

Answer:

Step-by-step explanation:

they want to know  a point on the line... that has a gradient ( think slope )  of -1/3  and has the point of (-2,5)  on it. So find the formula for that line

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5 0
3 years ago
What is the area? Please explain steps so I can attempt to understand
yarga [219]

Answer:

12 \sqrt{2}

Step-by-step explanation:

you can use hypotenuse formula

45-45-90 isosceles right triangle

so, 45= x

x² + x² = 24²

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x²= 24.12

x= \sqrt{288}  = 12 \sqrt{2}

or :

you can use this rule: if you see a 45 45 90 isosceles right triagngle (you can look picture) 45=a cm and 90 = a\sqrt{2}

cm

so ;

a \sqrt{2}  = 24

a= 12 \sqrt{2}

hope this helps ^-^

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Oh man this is complicated
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