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3 years ago

Is 0.12 a rational number

Mathematics

2 answers:

Ray Of Light [21]3 years ago

6 0

Yes .12 is a rational number

Bingel [31]3 years ago

4 0

Answer:

Step-by-step explanation:

Yea

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Marcos drove twice as far as Candice. Together, they drove 66 miles. Which equation can be used to find the number of miles Cand

galben [10]

Candice drove 22 miles. 66 divided by 3 is 22. Which means Marcos drove 44 miles.

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3 years ago

Chelsea shows her work in finding the solution to 4x-5=2+3(x-3). After checking her answer in the original equation, she found t

KonstantinChe [14]

Answer:

The solution is x=-2

The mistake could be in operation however here is the all operation

Step-by-step explanation:

Getting each term and sum each one

$4x-5=2+3(x-3)\\4x-5=2+3x-9\\4x-5=-7+3x\\4x-3x=-7+5\\x=-2$

Check replacing in the original equation:

$4(-2)-5=2+3(-2-3)\\-8-5=2-6-9\\-13=2-15\\-13=13$

3 0

3 years ago

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A student has 2 pounds of cereal. If the student eats 1/6 pound of cereal each day, how many days can the student eat cereal

harina [27]

Answer:

12 days

Step-by-step explanation:

1/6 per day

in 6 days- 1 pound

6x2=12 days=2 pounds

hope this helped :)

7 0

3 years ago

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How can a kepler-47c happen?? <br><br><br> Plz help :(

Natali5045456 [20]

Answer:

I'm not SUPER sure but, it only can exist where there is a region in a planetary system where liquid water might exist on the surface of a planet. That puts it in the "habitable zone" which is where it can exist.

6 0

3 years ago

Area of a triangle with points at (-9,5), (6,10), and (2,-10)

Ann [662]

First we are going to draw the triangle using the given coordinates.
Next, we are going to use the distance formula to find the sides of our triangle.
Distance formula: $d= \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Distance from point A to point B:
$d_{AB}= \sqrt{[6-(-9)]^2+(10-5)^2}$
$d_{AB}= \sqrt{(6+9)^2+(10-5)^2}$
$d_{AB}= \sqrt{(15)^2+(5)^2}$
$d_{AB}= \sqrt{225+25}$
$d_{AB}= \sqrt{250}$
$d_{AB}=15.81$

Distance from point A to point C:
$d_{AC}= \sqrt{[2-(-9)]^2+(-10-5)^2}$
$d_{AC}= \sqrt{(2+9)^2+(-10-5)^2}$
$d_{AC}= \sqrt{11^2+(-15)^2}$
$d_{AC}= \sqrt{121+225}$
$d_{AC}= \sqrt{346}$
$d_{AC}= 18.60$

Distance from point B from point C
$d_{BC}= \sqrt{(2-6)^2+(-10-10)^2}$
$d_{BC}= \sqrt{(-4)^2+(-20)^2}$
$d_{BC}= \sqrt{16+400}$
$d_{BC}= \sqrt{416}$
$d_{BC}=20.40$

Now, we are going to find the semi-perimeter of our triangle using the semi-perimeter formula:
$s= \frac{AB+AC+BC}{2}$
$s= \frac{15.81+18.60+20.40}{2}$
$s= \frac{54.81}{2}$
$s=27.41$

Finally, to find the area of our triangle, we are going to use Heron's formula:
$A= \sqrt{s(s-AB)(s-AC)(s-BC)}$
$A=\sqrt{27.41(27.41-15.81)(27.41-18.60)(27.41-20.40)}$
$A= \sqrt{27.41(11.6)(8.81)(7.01)}$
$A=140.13$

We can conclude that the perimeter of our triangle is 140.13 square units.

3 0

3 years ago