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3 years ago

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The measure of one angle of a triangle is 55 degrees. The measure of the third angle is 20 degrees more than twice the second an

gle. All three angles of a triangle must add to 180 degrees. Find the measures of the second and third angels.

1 answer:

sesenic [268]3 years ago

7 0

If 1 angle is 55 and another is 55 add 20 (75) if you added them together it would be 130 so do 180 - 130 hope this helped!!

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The letter answer is d

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3 years ago

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MArishka [77]

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Prove that:<br><br>cos20°cos40°cos80°=1/8

Naya [18.7K]

Answer:

see explanation

Step-by-step explanation:

Using the double angle identity for sine

sin2x = 2sinxcosx

Consider left side

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= $\frac{1}{2sin20}$ (2sin20°cos20°)cos40°cos80°

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= $\frac{1}{8sin20}$ . sin20°

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3 years ago

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These aren't solvable.

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4 years ago

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GuDViN [60]

Answer:

$\frac{-5 \pm \sqrt{13} }{6}$

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Step-by-step explanation:

<u>Step 1: Define</u>

<u /> $\frac{-5 \pm \sqrt{5^2-4(3)(1)} }{2(3)}$ <u />

<u />

<u>Step 2: Evaluate</u>

Evaluate Exponents: $\frac{-5 \pm \sqrt{25-4(3)(1)} }{2(3)}$
Evaluate Multiplication: $\frac{-5 \pm \sqrt{25-12} }{6}$
Evaluate Subtraction: $\frac{-5 \pm \sqrt{13} }{6}$

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3 years ago