Simplify. Consider all cases. |14−(x−6)|
2 answers:
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All the numbers in the first equation have a common factor of 2. Removing that gives
.. x +4y = 6
making it easy to solve for x
.. x = 6 -4y
My choice would be to solve for x using the first equation.
_____
On second thought, it might actually be easier to solve either equation for 8y. That term then directly substitutes into the other equation (equivalent to adding the two equations).
.. 8y = 3x -11 . . . . . from the second equation
.. 2x +(3x -11) = 12 . . . substituting into the first equation
.. 5x = 23 . . . . . . . . . . collect terms, add 11 (what you would get by adding the equations in the first place)
.. x = 4.6
.. y = (3*4.6 -11)/8 = 0.35
.. x +4y = 6
making it easy to solve for x
.. x = 6 -4y
My choice would be to solve for x using the first equation.
_____
On second thought, it might actually be easier to solve either equation for 8y. That term then directly substitutes into the other equation (equivalent to adding the two equations).
.. 8y = 3x -11 . . . . . from the second equation
.. 2x +(3x -11) = 12 . . . substituting into the first equation
.. 5x = 23 . . . . . . . . . . collect terms, add 11 (what you would get by adding the equations in the first place)
.. x = 4.6
.. y = (3*4.6 -11)/8 = 0.35
Answer:
segment a double prime b double prime = segment ab over 2
Step-by-step explanation:
Triangle A″B″C″ is formed using the translation (x + 2, y + 0) and the dilation by a scale factor of one half from the origin. which equation explains the relationship between segment ab and segment a double prime b double prime?
coordinate plane with triangle ABC at A (- 3, 3), B (1, - 3), and C (- 3, -3).
segment a double prime b double prime = segment ab over 2
segment ab = segment a double prime b double prime over 2
segment ab over segment a double prime b double prime = one half
segment a double prime b double prime over segment ab = 2
Answer: If triangle ABC at A (- 3, 3), B (1, - 3), and c (- 3, -3) is translated using (x + 2, y + 0), then the new coordinates of triangle ABC would be at A'(- 3 + 2, 3), B'(1 + 2, - 3), and C'(- 3 + 2, -3) Which is A'(- 1, 3), B'(3, - 3), and C'(- 1, -3). The dilation by a scale factor of from the origin gives A″ (-1/2, 3/2), B″ (3/2, -3/2) and C″(-1/2, -3/2) = (-0.5, 1.5), B″ (1.5, -1.5) and C″(-0.5, -1.5)
The distance AB and A"B" are given as:
AB = √52 = √(4×52) = 2√13 = 2A"B"
A"B" = AB/2