Fraction -> Decimal
4/5 = 0.8
1/8 = 0.125
Decimal -> Percent
0.22 * 100% = 22%
0.47 * 100% = 47%
Percent -> Fraction
34% / 100 = 0.34 = 17/50
25% / 100 = 0.25 = 1/4
Fraction -> Percent
1/3 = 0.33... * 100% = 33.3%
2/5 = 0.4 * 100% = 40%
Decimal -> Fraction
0.65 = 65/100 = 13/20
0.4 = 4/10 = 2/5
Percent -> Decimal
81% / 100 = 0.81
4% / 100 = 0.04
Best of Luck!
Answer:
a) Just add 1 square on the right and 1 square on top for figure 4. Add 1 more in each place for figure 5.
b) Each stage adds a square above and a square to the right. The pattern never decreases. This trend is shown by figures 1, 2, and 3.
c) Figure 0 would be a single square. Simply follow the pattern in reverse. As the figure number decreases, squares are removed from the right and the top rather than added.
Answer:
7x+6 = 5(x+6)
Step-by-step explanation:
x represents Harry's age now, so 7x represents Nick's age now. (Nick is 7 times as old as Harry.)
In 6 years, Harry's age will be x+6.
In 6 years, Nick's age will be 7x+6, which is 5 times Harry's age at that time, 5(x+6). Hence an appropriate equation is ...
... 7x+6 = 5(x+6)
_____
Please note that finding the value of x does not give the answer to the question. We are asked for Harry's age in 6 years, so the answer is x+6 (=18).
Answer:
1.15%
Step-by-step explanation:
To get the probability of m independent events you multiply the individual probability of each event. In this case we have m independent events, each one with the same probability, therefore:


This is a particlar scenario of binomial distribution problem. So the binomial distribution questions are about the number of success of m independent events, where every individual event has the same p probability. In the question we have 20 events and each event has a probability of 80%. The binomial distribution formula is:

n is the number of events
k is the number of success
p is the probability of each individual event
is the binomial coefficient
the binomial coefficient allows to find the subsets of k elements in a set of n elements. In this case there is only one subset possible since the only way to get 20 of 20 correct questions is to getting right all questions (for getting 19 of 20 questions there are many ways, for example getting the first question wrong and all the other questions right, or getting second questions wrong and all the other questions right, etc).

therefore, for this questions we have:
