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3 years ago

A box has a square base with an area of 16 sq.in. Its is 14 inches tall. what is the volume?

Mathematics

1 answer:

babunello [35]3 years ago

6 0

Answer:

224 inches cubed.

Step-by-step explanation:

Because the area of a square is 16 square inches, the side length is 4 inches. This is because a square's formula for area is the side squared.

Since the box is 14 inches tall, we multiply 4 inches by 4 inches by 14 inches. This means the answer is 224 inches cubed.

We also notice we don't need a measurement for the base sides, we only need to multiply the area by the height.

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Alan just got a Fall job. The equation P = 12.50h represents the salary P (in dollars) he will earn when he works h hours. How m

balandron [24]

Given:

Alan salary P (in dollars) when he works h hours is represented by the equation

$P=12.50h$

To find:

The earning per hour.

Solution:

We have,

$P=12.50h$

Here, P is total salary and h is number of hours he works.

$\text{Earning per hour}= \dfrac{\text{Total salary}}{\text{Number of hours}}$

$\text{Earning per hour}= \dfrac{12.50h}{h}$

$\text{Earning per hour}=12.50$

Therefore, the earning per hour is $12.50.

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2 years ago

A triangle has vertices (3,5), (5,2), and (2,0). Is the triangle a right triangle?

Artyom0805 [142]

Answer:

No, this is not a right triangle

Step-by-step explanation:

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2 years ago

Read 2 more answers

Find the number b such that the line y = b divides the region bounded by the curves y = 36x2 and y = 25 into two regions with eq

Gemiola [76]

Answer:

b = 15.75

Step-by-step explanation:

Lets find the interception points of the curves

36 x² = 25

x² = 25/36 = 0.69444

|x| = √(25/36) = 5/6

thus the interception points are 5/6 and -5/6. By evaluating in 0, we can conclude that the curve y=25 is above the other curve and b should be between 0 and 25 (note that 0 is the smallest value of 36 x²).

The area of the bounded region is given by the integral

$\int\limits^{5/6}_{-5/6} {(25-36 \, x^2)} \, dx = (25x - 12 \, x^3)\, |_{x=-5/6}^{x=5/6} = 25*5/6 - 12*(5/6)^3 - (25*(-5/6) - 12*(-5/6)^3) = 250/9$

The whole region has an area of 250/9. We need b such as the area of the region below the curve y =b and above y=36x^2 is 125/9. The region would be bounded by the points z and -z, for certain z (this is for the symmetry). Also for the symmetry, this region can be splitted into 2 regions with equal area: between -z and 0, and between 0 and z. The area between 0 and z should be 125/18. Note that 36 z² = b, then z = √b/6.

$125/18 = \int\limits^{\sqrt{b}/6}_0 {(b - 36 \, x^2)} \, dx = (bx - 12 \, x^3)\, |_{x = 0}^{x=\sqrt{b}/6} = b^{1.5}/6 - b^{1.5}/18 = b^{1.5}/9$