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damaskus [11]
3 years ago
13

A toy box contains eight green balls and four purple balls. Suppose you choose a ball at random and then replace it by putting i

t back in the toy box. You then choose a second ball. What is the probability that you have selected a green ball and then a purple ball?
Mathematics
1 answer:
Rus_ich [418]3 years ago
6 0

Answer:ye

Step-by-step explanation:

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alexandr402 [8]

Answer:

The answer is 2.

Step-by-step explanation:

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Subtract 43 from 20 raised to the 7th power; then multiply by 3.
viktelen [127]

Hi there! :)

<u>Answer:</u>

Subtract 43 from 20 raised to the 7th power; then multiply by 3. The answer is: <u>3,839,999,871</u>

Step-by-step explanation:

"Subtract" means to take away a number from another.

" 20 raised to the 7th power" is the same thing as 20 exponent 7: 20^{7}


SO, you want to take away 43 from 20^{7} and then multiply the answer by 3:

(20^{7} - 43) × 3

20^{7} = 1,280,000,000

(1,280,000,000 - 43) × 3

1,280,000,000 - 43 = 1,279,999,957

1,279,999,957 × 3

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There you go! I really hope this helped, if there's anything just let me know! :)

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Answer:

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Step-by-step explanation:

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