<span>The International Space Station orbits Earth at an altitude of 240 miles. If a camera were set up on the Space Station, Earth's horizon will be seen by the camera in a distance of </span><span>A. 480.31 miles.</span>
We have that
csc ∅=13/12
sec ∅=-13/5
cot ∅=-5/12
we know that
csc ∅=1/sin ∅
sin ∅=1/ csc ∅------> sin ∅=12/13
sec ∅=-13/5
sec ∅=1/cos ∅
cos ∅=1/sec ∅------> cos ∅=-5/13
sin ∅ is positive and cos ∅ is negative
so
∅ belong to the II quadrant
therefore
<span>the coordinates of point (x,y) on the terminal ray of angle theta are
</span>x=-5
y=12
the answer ispoint (-5,12)
see the attached figure
Answer:
x-intercepts = (x ≈ -0.87), (x ≈ 6.87)
Step-by-step explanation:
let x = 0, in equation for x-intercepts
solve for x using the
quadratic formula
x = <u>−6 ± √ 36 + 24 </u>
2x
= <u>−6 ± √60</u>
−2x
= <u>−6 ± 2 √ 15</u>
−2 = 3 ± √15
Answer:
I am not completely sure but I believe that it is C) 240 yd^3
Step-by-step explanation:
Answer:
24
Step-by-step explanation:
area = wl (6×4 = 24)
w width l length