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2 years ago

Please help me with this

Mathematics

2 answers:

masha68 [24]2 years ago

7 0

Answer:

Step-by-step explanation:

10x-11+3x-2+3x+1=180

16x-12=180

16x=192

x=12

Luba_88 [7]2 years ago

5 0

Answer:

Step-by-step explanation:

The sum of three angles is 180°

(3x + 1) + (3x-2) + (10x -11) = 180°

16x -12 = 180

16x = 192

x = 12

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Solve for a: a(a-3) =100

marissa [1.9K]

$a(a-3) =100\\
a^2-3a-100=0\\
\Delta=(-3)^2-4\cdot1\cdot(-100)=9+400=409\\
\sqrt{\Delta}=\sqr{409}\\
a_1=\dfrac{-(-3)-\sqrt{409}}{2\cdot1}=\dfrac{3-\sqrt{409}}{2}\\
a_2=\dfrac{-(-3)+\sqrt{409}}{2\cdot1}=\dfrac{3+\sqrt{409}}{2}$

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3 years ago

Please help me now ! Thank you

jarptica [38.1K]

First we'll do two basic steps. Step 1 is to subtract 18 from both sides. After that, divide both sides by 2 to get x^2 all by itself. Let's do those two steps now

2x^2+18 = 10
2x^2+18-18 = 10-18 <<--- step 1
2x^2 = -8
(2x^2)/2 = -8/2 <<--- step 2
x^2 = -4

At this point, it should be fairly clear there are no solutions. How can we tell? By remembering that x^2 is never negative as long as x is real.

Using the rule that negative times negative is a positive value, it is impossible to square a real numbered value and get a negative result.

For example
2^2 = 2*2 = 4
8^2 = 8*8 = 64
(-10)^2 = (-10)*(-10) = 100
(-14)^2 = (-14)*(-14) = 196

No matter what value we pick, the result is positive. The only exception is that 0^2 = 0 is neither positive nor negative.

So x^2 = -4 has no real solutions. Taking the square root of both sides leads to

x^2 = -4
sqrt(x^2) = sqrt(-4)
|x| = sqrt(4)*sqrt(-1)
|x| = 2*i
x = 2i or x = -2i
which are complex non-real values

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3 years ago

Danny opened a savings account with $50 and depositedn$10 each week for 4 weeks

Romashka [77]

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3 years ago

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Consider function g. Which function could be the inverse of function g? PLEASE HELP !

Bingel [31]

Answer:

The answer is D

Step-by-step explanation:

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3 years ago

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I don’t understand this someone pls help me! (Question 10)

Likurg_2 [28]

Answer:

a. f(n) = n(n+1)/2

b. 351

c. 19

d. no; n would not be an integer for f(n) = 17.

Step-by-step explanation:

a. The terms are 1, 3, 6, 10, ...

Each term has the term number added to the previous term. That is, first differences are 3-1 = 2, 6-3 = 3, 10-6 = 4. These differences have a constant difference of 1.

When the 2nd differences are constant, a 2nd degree polynomial can describe the sequence. It is a little bit of trouble to find that polynomial.

For the polynomial ...

$f(n)=an^2+bn+c$

We can substitute values for n and f(n) to get 3 equations in 3 unknowns:

$1=a\cdot1^2+b\cdot1+c\\\\3=a\cdot2^2+b\cdot2+c\\\\6=a\cdot3^2+b\cdot3+c$

Solving these equations by your favorite method gives ...

(a, b, c) = (1/2, 1/2, 0)

That is, the function representing the relationship is ...

f(n) = n(n+1)/2 . . . . the function describing the relationship

b. f(26) = 26(27) = 13(27) = 351 . . . . the number of squares in term 26

c. The number of the term having 190 squares can be found by solving ...

n(n +1)/2 = 190

n(n +1) = 380 = 19(20)

The 19th term will have 190 squares.

d. Terms 5 and 6 are 15 and 21.

17 is not the value of one of the terms in this sequence.

6 0

2 years ago