The common ratio is: $\mathbf{r = \frac{a + 5d}{a + d}}$
The general term of the GP is: $\mathbf{a_n = (a + d) \times (\frac{a + 5d}{a + d})^{n-1}}$

The nth term of an AP is:

$\mathbf{T_n = a + (n - 1)d}$

So, the 2nd, 6th and 8th terms of the AP are:

$\mathbf{T_2 = a + d}$

$\mathbf{T_6 = a + 5d}$

$\mathbf{T_8 = a + 7d}$

The first, second and third terms of the GP would be:

$\mathbf{a_1 = a + d}$

$\mathbf{a_2 = a + 5d}$

$\mathbf{a_3 = a + 7d}$

The common ratio (r) is calculated as:

$\mathbf{r = \frac{a_2}{a_1}}$

This gives

$\mathbf{r = \frac{a + 5d}{a + d}}$

The nth term of a GP is calculated using:

$\mathbf{a_n = a_1r^{n-1}}$

So, we have:

$\mathbf{a_n = (a + d) \times (\frac{a + 5d}{a + d})^{n-1}}$

Read more about arithmetic and geometric progressions at:

6 0

3 years ago

Aleonysh [2.5K]

What does this even mean?

7 0

3 years ago

Reil [10]

Step-by-step explanation:

see the answer in the pic

4 0

3 years ago