(1/3) bag = (1/4) lb.
multiply by 3 on both sides to get 1 full bag.
3(1/3)b = 3(1/4)
1 bag = (3/4) lb.
To solve this question, we have to find the equation of the circle with given center and where it passes. Doing this, we get that the equation of the circle is:

Equation of a circle:
The equation of a circle with center
and radius r is given by:

Center at (16, 30)
This means that 
Thus

Passes through the origin:
We use this to find the radius squared, as this means that
is part of the circle. Thus



Thus, the equation of the circle is:

For another example to find the equation of a circle, you can look at brainly.com/question/23719612
Answer:
Step-by-step explanation:
If slope of two lines are equal, then they are parallel lines.
If product of the slope of two lines is (-1), then they are perpendicular lines.
C) y = x + 2
Slope m1 = 1
y = -x + 3
Slope m2 = -1
m1 * m2 = 1 * (-1) = -1
These are perpendicular lines.
D) y = 3x + 2
Slope = m1 = 3
y = 3x - 2
Slope = m2 = 3
Slopes are equal. So, they are parallel lines.
E)y= 3
This line is parallel to x -axis.
x = 4
This line is parallel to y-axis.
So, both lines are perpendicular to each other.
F) y = x + 8
slope m1 = 1
y = -x + 3
Slope = m2 = -1
M1 * m2 = 1 * (-1) = -1
So, These are perpendicular lines
Answer:
The particle will travel 6 feet in first 2 seconds.
Step-by-step explanation:
We have been given that a particle moves according to the velocity equation
. We are asked to find the distance that the particle will travel in its first 2 seconds.


Now, we will eliminate the absolute value sign as:

![s(t)=[\frac{6t^3}{3}-\frac{18t^2}{2}+12t]^1_0 +[\frac{-6t^3}{3}+\frac{18t^2}{2}-12t]^2_1](https://tex.z-dn.net/?f=s%28t%29%3D%5B%5Cfrac%7B6t%5E3%7D%7B3%7D-%5Cfrac%7B18t%5E2%7D%7B2%7D%2B12t%5D%5E1_0%20%2B%5B%5Cfrac%7B-6t%5E3%7D%7B3%7D%2B%5Cfrac%7B18t%5E2%7D%7B2%7D-12t%5D%5E2_1)
![s(t)=[2t^3-9t^2+12t]^1_0 +[-2t^3+9t^2-12t]^2_1](https://tex.z-dn.net/?f=s%28t%29%3D%5B2t%5E3-9t%5E2%2B12t%5D%5E1_0%20%2B%5B-2t%5E3%2B9t%5E2-12t%5D%5E2_1)





Therefore, the particle will travel 6 feet in first 2 seconds.
Oops someone else answered it before me